比较bash，diff和相同值的三个数组 [英] Compare three arrays in bash, diff and identical values

问题描述

此问题是指已回答的问题: 比较/区别bash中两个数组

This question refers to the answered question: Compare/Difference of two arrays in bash

让我们看两个数组:

Array1=( "key1" "key2" "key3" "key4" "key5" "key6" "key7" "key8" "key9" "key10" "key13" )
Array2=( "key1" "key2" "key3" "key4" "key5" "key6" "key11" "key12" "key13" )

数组之间的对称差异:

Array3=(`echo ${Array1[@]} ${Array2[@]} | tr ' ' '\n' | sort | uniq -u `)

Array3值:

echo $Array3
key10
key11
key12
key7
key8
key9

仅在Array1中的值:

Values only in Array1:

echo ${Array1[@]} ${Array3[@]} | tr ' ' '\n' | sort | uniq -D | uniq
key10
key7
key8
key9

仅在Array2中的值

Values only in Array2

echo ${Array2[@]} ${Array3[@]} | tr ' ' '\n' | sort | uniq -D | uniq
key11
key12

我的问题是，我们如何获取Array1&中的值? Array2但不在Array3中(相同)? 预期结果:

My question, how can we get values that are in Array1 & Array2 but not in Array3 (identical)? Expected result:

key1
key13
key2
key3
key4
key5
key6

感谢您的帮助.

推荐答案

几次测试后确定，看来我要找的答案只是:

OK after few test, it seems the answer I was looking for was just:

echo ${Array1[@]} ${Array2[@]} | tr ' ' '\n' | sort | uniq -D | uniq
key1
key13
key2
key3
key4
key5
key6

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