将一个数组分组以根据索引形成三个数组 [英] Group an array to form three arrays based on the index

问题描述

我想对数组进行排序，使其返回三个数组.所以

I want to sort an array in a way that it gives back three arrays. So

var myArray = ['1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3','1','2','3'];

此处的值可以是数字，字符串，对象等.

here the values can be numbers, string, objects etc.

我想要三个数组，例如:

I want three arrays Like :

var myArray1 = ['1','1','1','1','1','1','1','1','1','1'];
var myArray2 = ['2','2','2','2','2','2','2','2','2','2'];
var myArray3 = ['3','3','3','3','3','3','3','3','3','3'];

推荐答案

您可以创建一个通用函数，该函数将根据提供的 n 对数组进行分组.根据 index％n 的结果，将它们推入特定的数组.在这里， n = 3 .如果您使用 i％2 ，这将根据奇数和偶数索引将数字分布到2个数组中.

You could create a generic function which will group the array based on the n provided. Based on the result of index % n, push them into specific arrays. Here, n = 3. If you use i % 2, this will distribute the numbers into 2 arrays based on odd and even indices.

const myArray = ['1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3', '1', '2', '3'];

function group(array, n) {
  return myArray.reduce((acc, number, i) => {
    acc[i % n] = acc[i % n] || [];
    acc[i % n].push(number);
    return acc;
  }, [])
}

const grouped = group(myArray, 3);

console.log(JSON.stringify(grouped[0]))
console.log(JSON.stringify(grouped[1]))
console.log(JSON.stringify(grouped[2]))

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