将一个数组分配给另一个数组 C++ [英] Assigning one array to another array c++

问题描述

你好，我是 C++ 的初学者，谁能给我解释一下

Hello I am beginner in c++ , can someone explain to me this

char a[]="Hello";

char b[]=a; // is not legal 

然而，

char a[]="Hello";

char* b=a; // is legal 

如果一个数组不能被复制或分配给另一个数组，为什么它可以作为参数传递，其中传递的值的副本总是在方法中进行

If a array cannot be copied or assigned to another array , why is it so that it is possible to be passed as a parameter , where a copy of the value passed is always made in the method

void copy(char[] a){....}

char[] a="Hello";

copy(a);

推荐答案

它不是复制数组；它把它变成了一个指针.如果你修改它，你会亲眼看到:

It isn't copying the array; it's turning it to a pointer. If you modify it, you'll see for yourself:

void f(int x[]) { x[0]=7; }
...
int tst[] = {1,2,3};
f(tst); // tst[0] now equals 7

如果需要复制数组，使用std::copy:

If you need to copy an array, use std::copy:

int a1[] = {1,2,3};
int a2[3];
std::copy(std::begin(a1), std::end(a1), std::begin(a2));

如果您发现自己这样做，您可能需要使用 std::array.

If you find yourself doing that, you might want to use an std::array.

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