为什么不允许乘法？ [英] Why multiplication not allowed?
问题描述
为什么不允许乘法指针？
直到现在我才知道这一点，但不是原因！
PS：作为一项规则，我搜索了常见问题解答，但无法找到答案。
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Vijay Kumar R Zanvar
我的主页 - http://www.geocities.com/vijoeyz/
推荐答案
" Vijay Kumar R Zanvar" < 6 ***** @ hotpop.com>写道：
"Vijay Kumar R Zanvar" <vi*****@hotpop.com> writes:
为什么不允许乘法指针？
直到现在我才知道这一点，但不是原因！
Why multiplication of pointers is not allowed?
Till now I only know this, but not the reason why!
指针乘法意味着什么？
What would multiplication of pointers mean?
Ben Pfaff < bl*@cs.stanford.edu>在消息中写道
news：87 ************ @ pfaff.stanford.edu ...
"Ben Pfaff" <bl*@cs.stanford.edu> wrote in message
news:87************@pfaff.stanford.edu...
" Vijay Kumar R Zanvar" < 6 ***** @ hotpop.com>写道：
"Vijay Kumar R Zanvar" <vi*****@hotpop.com> writes:
为什么不允许乘法指针？
直到现在我才知道这一点，但不是原因！
Why multiplication of pointers is not allowed?
Till now I only know this, but not the reason why!
指针乘法是什么意思？
What would multiplication of pointers mean?
#include< stdio.h>
#include< stdlib.h>
int
main（无效）
{
int i = 10;
int * k =& i，* j =& i;
k = k * j;
返回EXIT_SUCCESS;
}
这给出了一个错误：
ptr_mul.c：在函数`main''中：
ptr_mul.c：10：错误：无效操作数到二进制*
#include <stdio.h>
#include <stdlib.h>
int
main ( void )
{
int i = 10;
int *k = &i, *j = &i;
k = k * j;
return EXIT_SUCCESS;
}
This gives an error:
ptr_mul.c: In function `main'':
ptr_mul.c:10: error: invalid operands to binary *
" Vijay Kumar R Zanvar" < 6 ***** @ hotpop.com>写道：
"Vijay Kumar R Zanvar" <vi*****@hotpop.com> writes:
" Ben Pfaff" < bl*@cs.stanford.edu>在消息中写道
新闻：87 ************ @ pfaff.stanford.edu ...
"Ben Pfaff" <bl*@cs.stanford.edu> wrote in message
news:87************@pfaff.stanford.edu...
" Vijay Kumar R Zanvar" < 6 ***** @ hotpop.com>写道：
"Vijay Kumar R Zanvar" <vi*****@hotpop.com> writes:
为什么不允许乘法指针？
直到现在我才知道这一点，但不是原因！
指针乘法意味着什么？
Why multiplication of pointers is not allowed?
Till now I only know this, but not the reason why!
What would multiplication of pointers mean?
#include< stdio.h>
#include< stdlib.h>
int
main（void）
{
int i = 10;
int * k =& i，* j =& i;
k = k * j;
#include <stdio.h>
#include <stdlib.h>
int
main ( void )
{
int i = 10;
int *k = &i, *j = &i;
k = k * j;
你的意思是
* k = * k * * j;
换句话说，乘以`int'，不是指向`int'的指针。
返回EXIT_SUCCESS;
}
You mean
*k = *k * *j;
In other words, multiply `int''s, not pointers to `int''s.
return EXIT_SUCCESS;
}
指针和它们的指示物之间的区别很大
基本面。您是否考虑过阅读课本或参加
课程？
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我没有C& V方便，但我有Dan Pop。
--E。 Gibbons
The difference between pointers and their referents is pretty
fundamental. Have you considered reading a textbook or taking a
class?
--
"I don''t have C&V for that handy, but I''ve got Dan Pop."
--E. Gibbons
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