为什么不允许继承成员？ [英] Why is inherited member not allowed?

问题描述

我是C ++的初学者，我正在做一个关于抽象类和继承的练习。

I'm beginner to C++ and I'm doing one of the exercises about abstract class and inheritance.

这是我的抽象类：

#ifndef   SHAPE_H 
#define  SHAPE_H
class Shape
{
    public:
        virtual void area();
        virtual void perimeter();
        virtual void volume();
};
#endif

这是我实现抽象类的具体类：

This is my concrete class that implements the abstract class:

#include <iostream>
#include <cmath>
#include "Shape.h"
using namespace std;

class Circle : public Shape
{
    public:
        Circle(int);
    private:
        int r;
};

Circle::Circle(int rad)
{
    r = rad;
}

void Circle::area()
{
    cout << "Area of this cirle = " << 3.14 * pow(r, 2) << endl;
}

void Circle::perimeter()
{
    cout << "Perimeter of this cirle = " << 2 * 3.14 * r << endl;
}

void Circle::volume()
{
    cout << "Volume is not defined for circle." << endl;
}

code>，，，（ / code>类，它显示错误：不允许继承成员。我经历了我的类ppt和谷歌的答案，但没有运气。

I got red lines under area(), perimeter(), and volume() in my Circle class, which showed "Error: inherited member is not allowed". I went through my class ppt and googled for answer but no luck. Any help is appreciated.

推荐答案

您必须将重写的函数声明为类定义的一部分

You have to declare the over-ridden functions as part of your class definition

class Circle : public Shape
    {
    public:
        Circle(int);
        virtual void area(); // overrides Shape::area
        void perimeter();    // overrides Shape::perimeter
        virtual void volume();
    private:
        int r;
    };

请注意，使用 virtual 可选。

如nm注意，你还应该在 Shape 中包含一个虚拟析构函数。您可能还希望使其虚拟函数纯虚拟（基于您对 Shape 的抽象的注释）

As n.m. noted, you should also include a virtual destructor in Shape. You may also want to make its virtual functions pure virtual (based on your comment about Shape being abstract)

class Shape
{
public:
    virtual ~Shape() {}
    virtual void area() = 0;
    virtual void perimeter() = 0;
    virtual void volume() = 0;
};

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