如何从long中提取字节？ [英] How to extract bytes from long?
问题描述
如何从最后一个字节开始从long中提取字节？
例如，我有一个很长的数字：
0x12345678
我需要将它表示为以下字节列表：
0x78,0x56,0x34,0x12
提前致谢，
Rita
How to extract bytes from long, starting from the last byte?
For example, I have a long number:
0x12345678
I need to represent it as the following bytes list:
0x78, 0x56, 0x34, 0x12
Thanks in advance,
Rita
推荐答案
RB写道：
如何从最后一个字节开始从long中提取字节？
例如，我有一个很长的数字：
0x12345678
我需要将它表示为以下字节列表：
0x78,0x56,0x34,0x12
谢谢提前，
Rita
How to extract bytes from long, starting from the last byte?
For example, I have a long number:
0x12345678
I need to represent it as the following bytes list:
0x78, 0x56, 0x34, 0x12
Thanks in advance,
Rita
查看按位运算符。 &，|，^，<<，>>。然后查看位掩码
以及如何使用它们，一切都应该相当简单。
-
Thomas。
未来所有语言的存在是什么
Look at bitwise operators. &, |, ^, <<, >>. Then look up bitmasks
and how to use them and everything should be rather straightforward.
--
Thomas.
"What is the future c existence which does not do in all languages"
2003年10月15日星期三01:59 ：04：0700，RB写道：
On Wed, 15 Oct 2003 01:59:04 -0700, RB wrote:
如何从最后一个字节开始从long中提取字节？
How to extract bytes from long, starting from the last byte?
＃ include< stdio.h>
int main（）{
无符号长值= 0x12345678;
int i;
printf（"％＃lx \ n"，value）;
for（i = sizeof value; i > 0; --i）{
printf（"％＃x \ n"，value& 0xff）;
value>> = 8 ;
}
返回0;
}
-
NPV
大字印刷品，小字体带走
Tom Waits - 向上走吧
RB写道：
RB wrote:
如何从最后一个字节开始从long中提取字节？
例如，我有一个很长的数字：
0x12345678
我需要将它表示为以下字节列表：
0x78,0x56,0x34,0x12
谢谢提前，
丽塔
How to extract bytes from long, starting from the last byte?
For example, I have a long number:
0x12345678
I need to represent it as the following bytes list:
0x78, 0x56, 0x34, 0x12
Thanks in advance,
Rita
听起来有点作业 - 但是作为一个提示试试这个：
#include< stdio.h>
int main（无效）
{
长val = 0x12345678;
printf（" 0x％x \ n"，val>> 16& 0xff）;
返回0;
}
问候，
Ed。
Sounds a bit homework-y, but as a hint try this:
#include <stdio.h>
int main(void)
{
long val=0x12345678;
printf("0x%x\n",val >> 16 & 0xff );
return 0;
}
Regards,
Ed.
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