反向字符串，如何打印字符串而不是小数？ [英] reverse string, how to print string and not decimals?

问题描述

char * reverse（char * str）{

int length = strlen（str）;

char * acc [length];

int i;

for（i = 0; i< = length-1; i ++）{

acc [length-1-i] = str [i];

}

返回acc;

}


如何打印字符串而不是小数点？如果我在for循环中添加printf，它会打印小数。它们是颠倒的，所以它有效，但是我想要打印字符。

解决方案

ssecorp写道：
< blockquote class =post_quotes>
char * reverse（char * str）{

int length = strlen（str）;

char * acc [length] ;

int i;

for（i = 0; i< = length-1; i ++）{

acc [length-1- i] = str [i];

}

返回acc;

}


如何然后我打印一个字符串而不是小数？如果我在for循环中添加printf，它会打印小数。它们是颠倒的，所以它有效，但我想要打印字符。

向我们展示代码。你所拥有的没有printf（）。


Brian

默认用户 < de *********** @ yahoo.comwrote in message

news：6f ************ @ mid.individual.net。 ..

> char * acc [length];

哎呀！

Mark B [Diputsur]写道：

>

" Default User" < de *********** @ yahoo.comwrote in message

news：6f ************ @ mid.individual.net。 ..

char * acc [length];

哎呀！

我当然不写那个。


Brian

char* reverse(char* str) {
int length = strlen(str);
char* acc[length];
int i;
for (i=0; i<=length-1; i++){
acc[length-1-i] = str[i];
}
return acc;
}

How do I then print a string and not decimals? If I add printf inside
the for loop it prints decimals. they are reversed so it works but I
want to prin chars.

解决方案

ssecorp wrote:

char* reverse(char* str) {
int length = strlen(str);
char* acc[length];
int i;
for (i=0; i<=length-1; i++){
acc[length-1-i] = str[i];
}
return acc;
}

How do I then print a string and not decimals? If I add printf inside
the for loop it prints decimals. they are reversed so it works but I
want to prin chars.

Show us the code. There is no printf() in what you have.


Brian

"Default User" <de***********@yahoo.comwrote in message
news:6f************@mid.individual.net...

> char* acc[length];

Oops!

Mark B [Diputsur] wrote:

>
"Default User" <de***********@yahoo.comwrote in message
news:6f************@mid.individual.net...

char* acc[length];

Oops!

I most certainly did NOT write that.

Brian

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