TASM打印字符串 [英] TASM Print characters of string

问题描述

我正在尝试逐个字符地打印一个字符串，并对其进行遍历.这就是我所拥有的:

I'm trying to print a string character by character, iterating through it. This is what I've got:

.MODEL SMALL
.STACK 64
.DATA
    string DB 'Something',0
    len equ $-string

.CODE

    xor bx, bx    
    mov si, offset string
Char:
    mov al, byte[si + bx]
    inc bx
    cmp bx, len
    je Fin

    mov ah, 2
    mov dl, al
    int 21h

    jmp Char

Fin:
    mov ax, 4c00h
    int 21h
END

我不知道我是否得到正确的字符串mem引用，因为它只显示奇怪的符号.我尝试将30加到dl，以为那是因为ascii表示.

I don't know if I'm getting the right mem reference of string, because it only shows me weird symbols. I tried adding 30 to dl, thinking it was because of the ascii representation.

如何按字符打印字符?

推荐答案

下面是Tasm的一个有效示例，它不会破坏字符串的开头.

Here is a working example with Tasm, that is not mangling the begining of the string.

由于以后移动增量并将je替换为jnz

It has one less jump due to the moving of the increment later and the replacement of the je with a jnz

.MODEL SMALL
.STACK 64
.DATA
    string DB 'Something'
    len equ $-string

.CODE

Entry:
    mov ax, @data   ;make DS point to our DATA segment
    mov ds, ax

    xor bx, bx      ;bx <-- 0
    mov si, offset string ;address of string to print

    mov ah, 2       ;we will use repeatedly service #2 of int 21h

Char:
    mov dl, [si + bx] ;dl is the char to print
    int 21h         ;ask DOS to output a single char

    inc bx          ;point to next char
    cmp bx, len     
    jnz Char        ;loop if string not finished

    mov ax, 4c00h
    int 21h         ;DOS exit program with al = exit code

END Entry

这篇关于TASM打印字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！