按第n项拆分列表 [英] spliting a list by nth items
问题描述
我觉得以前可能已经回答了这个问题，但是我无法在档案中找到类似的东西。如果你知道这已经被解答了，请随意指点我
。
我有一个特定顺序的列表，我想拆分成两个
列表：每个第n项的列表，以及剩余项目的列表。
维护两个列表中的原始订单非常重要。
所以第一个清单很简单：
nth_items = items [:: n]
第二个列表是给我带来麻烦的。到目前为止，我提出的最好的价格是：
non_nth_items = list（items）
del non_nth_items [:: n]
这是正确的方法吗？
史蒂夫
-
如果你只是动词，你可以将任何字面化。
- Bucky Katt，Get Fuzzy
< blockquote> Steven Bethard写道：
我觉得这可能之前已经得到了解答，但我无法在档案中找到类似的东西。如果你知道这已经得到了解答，请随时指点我
我有一个特定顺序的列表，我想分成两个列表：每个第n项的清单，以及剩余项目的清单。
在两个清单中维护原始订单非常重要。
所以第一个清单很简单：
nth_items = items [:: n]
第二个清单是给我带来麻烦的。到目前为止，我提出的最好的是：
non_nth_items = list（items）
del non_nth_items [:: n]
这是正确的方法吗？
可能没有正确的办法。我认为，你的方式不是我想要做的事情。但它很棒。 :-)
（也很简单明了。）
-Peter
Steven Bethard写道：
我有一个特定顺序的列表，我想分成两个
列表：每个第n项的列表，以及剩余项目的列表。保持两个列表中的原始顺序非常重要。
所以第一个列表很简单：
nth_items = items [:: n]
第二个清单是给我带来麻烦的。
non_nth_items = [如果是x％n，x为x项目中的x]
-
Michael Hoffman
我相信你的意思是：
non_nth_items = [items [i-1] for i in range（1，len（items）-1）if i％n]
我不认为if x％n不能在他的物品清单上工作
拉里贝茨
"迈克尔霍夫曼" < m。********************************* @ example.com>写在
消息新闻：ci ********** @ pegasus.csx.cam.ac.uk ...Steven Bethard写道：
我有一个特定顺序的列表，我想分成两个
列表：每个第n个项目的列表，以及剩余项目的列表。保持两个列表中的原始顺序非常重要。
所以第一个列表很简单：
nth_items = items [:: n]
第二个清单是给我带来麻烦的。
non_nth_items = [如果是x％n，x为x项目中的x]
-
Michael Hoffman
I feel like this has probably been answered before, but I couldn''t
find something quite like it in the archives. Feel free to point me
somewhere if you know where this has already been answered.
I have a list in a particular order that I want to split into two
lists: the list of every nth item, and the list of remaining items.
It''s important to maintain the original order in both lists.
So the first list is simple:
nth_items = items[::n]
The second list is what''s giving me trouble. So far, the best I''ve
come up with is:
non_nth_items = list(items)
del non_nth_items[::n]
Is this the right way to do this?
Steve
--
You can wordify anything if you just verb it.
- Bucky Katt, Get Fuzzy
Steven Bethard wrote:I feel like this has probably been answered before, but I couldn''t
find something quite like it in the archives. Feel free to point me
somewhere if you know where this has already been answered.
I have a list in a particular order that I want to split into two
lists: the list of every nth item, and the list of remaining items.
It''s important to maintain the original order in both lists.
So the first list is simple:
nth_items = items[::n]
The second list is what''s giving me trouble. So far, the best I''ve
come up with is:
non_nth_items = list(items)
del non_nth_items[::n]
Is this the right way to do this?
There''s probably no "right" way. Your way isn''t the way I
would have thought to do it, I think. But it''s brilliant. :-)
(Also simple and clear.)
-Peter
Steven Bethard wrote:
I have a list in a particular order that I want to split into two
lists: the list of every nth item, and the list of remaining items.
It''s important to maintain the original order in both lists.
So the first list is simple:
nth_items = items[::n]
The second list is what''s giving me trouble.
non_nth_items = [x for x in items if x % n]
--
Michael Hoffman
I believe you meant somthing like:
non_nth_items = [items[i-1] for i in range(1,len(items)-1) if i % n]
I don''t think the "if x % n" won''t work on his list of items
Larry Bates
"Michael Hoffman" <m.*********************************@example.com > wrote in
message news:ci**********@pegasus.csx.cam.ac.uk...Steven Bethard wrote:I have a list in a particular order that I want to split into two
lists: the list of every nth item, and the list of remaining items. It''s
important to maintain the original order in both lists.
So the first list is simple:
nth_items = items[::n]
The second list is what''s giving me trouble.
non_nth_items = [x for x in items if x % n]
--
Michael Hoffman
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