Python：数组中的拆分列表 [英] Python: Split list in array

问题描述

从python开始，知道我知道什么都不知道。我想找到将列表分成列表列表的其他方式。示例列表：

Just beginning with python and know enough to know I know nothing. I would like to find alternative ways of splitting a list into a list of dicts. Example list:

data = ['**adjective:**', 'nice', 'kind', 'fine',
        '**noun:**', 'benefit', 'profit', 'advantage', 'avail', 'welfare', 'use', 'weal', 
        '**adverb:**', 'well', 'nicely', 'fine', 'right', 'okay'] 

我可以得到：

[{'**adjective**': ('nice', 'kind', 'fine'),
 '**noun**': ('benefit', 'profit', 'advantage', 'avail', 'welfare', 'use', 'weal'),
 '**adverb**': ('well', 'nicely', 'fine', 'right', 'okay')}] 

推荐答案

这可能是一样接近你所问的：

This might be as close at it gets to what you have asked:

d = collections.defaultdict(list)
for s in data:
    if s.endswith(":"):
        key = s[:-1]
    else:
        d[key].append(s)
print d
# defaultdict(<type 'list'>, 
#     {'adjective': ['nice', 'kind', 'fine'], 
#      'noun': ['benefit', 'profit', 'advantage', 'avail', 'welfare', 'use', 'weal'], 
#      'adverb': ['well', 'nicely', 'fine', 'right', 'okay']})

编辑： - 由SilentGhost的答案启发：

Just for fun an alternative two-liner inspired by the answer by SilentGhost:

g = (list(v) for k, v in itertools.groupby(data, lambda x: x.endswith(':')))
d = dict((k[-1].rstrip(":"), v) for k, v in itertools.izip(g, g))

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