python映射字符串拆分列表 [英] python map string split list

问题描述

我正在尝试将str.split函数映射到字符串数组.即，我想将所有字符串拆分为遵循相同格式的字符串数组.知道如何在python中使用map做到这一点吗?例如，假设我们有一个这样的列表:

I am trying to map the str.split function to an array of string. namely, I would like to split all the strings in a string array that follow the same format. Any idea how to do that with map in python? For example let's assume we have a list like this:

>>> a = ['2011-12-22 46:31:11','2011-12-20 20:19:17', '2011-12-20 01:09:21']

想使用map按空格将字符串拆分(split("))，以使列表为:

want to split the strings by space ( split(" ")) using map to have a list as:

>>> [['2011-12-22', '46:31:11'], ['2011-12-20', '20:19:17'], ['2011-12-20', '01:09:21']]

推荐答案

尽管尚不为人所知，但有一个功能专门为此目的而设计，

Though it isn't well known, there is a function designed just for this purpose, operator.methodcaller:

>>> from operator import methodcaller
>>> a = ['2011-12-22 46:31:11','2011-12-20 20:19:17', '2011-12-20 01:09:21']
>>> map(methodcaller("split", " "), a)
[['2011-12-22', '46:31:11'], ['2011-12-20', '20:19:17'], ['2011-12-20', '01:09:21']]

此技术比使用lambda表达式的等效方法要快.

This technique is faster than equivalent approaches using lambda expressions.

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