按索引列表拆分字符串 [英] Splitting a string by list of indices

问题描述

我想通过索引列表拆分字符串，其中拆分段以一个索引开始并在下一个索引之前结束.

I want to split a string by a list of indices, where the split segments begin with one index and end before the next one.

示例:

s = 'long string that I want to split up'
indices = [0,5,12,17]
parts = [s[index:] for index in indices]
for part in parts:
    print part

这将返回:

我想拆分的长字符串
我想拆分的字符串
我想分手
我想分手

long string that I want to split up
string that I want to split up
that I want to split up
I want to split up

我正在尝试:

长
字符串
那个
我想分手

long
string
that
I want to split up

推荐答案

s = 'long string that I want to split up'
indices = [0,5,12,17]
parts = [s[i:j] for i,j in zip(indices, indices[1:]+[None])]

返回

['long ', 'string ', 'that ', 'I want to split up']

您可以使用:

print '\n'.join(parts)

另一种可能性(不复制索引)是:

Another possibility (without copying indices) would be:

s = 'long string that I want to split up'
indices = [0,5,12,17]
indices.append(None)
parts = [s[indices[i]:indices[i+1]] for i in xrange(len(indices)-1)]

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