如何将二进制编码的十六进制字节数组转换为字节 [英] How to Convert Binary Coded Hex Byte Array to Byte
问题描述
我认为这将是直截了当的，因为在.NET中有丰富的转换功能，但事实证明它比想象的更糟糕。
想象。给予以下
< code>
Dim ba（1）As Byte
Dim b As Byte
ba（0）=& h4
ba（1）=& h0
b = foo（ba）
< / code>
什么是foo（），b包含& h40？
TIA
Charles
[我可以为此编写一个算法，但必须有一个简洁的
为它转换]
I thought this was going to be straight forward, given the wealth of
conversion functions in .NET, but it is proving more convoluted than
imagined.
Given the following
<code>
Dim ba(1) As Byte
Dim b As Byte
ba(0) = &h4
ba(1) = &h0
b = foo(ba)
</code>
What is foo() such that b contains &h40 ?
TIA
Charles
[I could write an algorithm for this, but there must surely be a succinct
conversion for it]
推荐答案
*" Charles Law" < BL *** @ nowhere.com> scripsit：
* "Charles Law" <bl***@nowhere.com> scripsit:
考虑到.NET中丰富的转换功能，我认为这将是直截了当的，但事实证明它比想象的更复杂。
给出以下内容
< code>
Dim ba（1）As Byte
Dim b As Byte
ba（0 ）=& h4
ba（1）=& h0
b = foo（ba）
< / code>
什么是foo（）这样b包含& h40？
TIA
[我可以为此写一个算法，但肯定有一个简洁的
转换它]
I thought this was going to be straight forward, given the wealth of
conversion functions in .NET, but it is proving more convoluted than
imagined.
Given the following
<code>
Dim ba(1) As Byte
Dim b As Byte
ba(0) = &h4
ba(1) = &h0
b = foo(ba)
</code>
What is foo() such that b contains &h40 ?
TIA
Charles
[I could write an algorithm for this, but there must surely be a succinct
conversion for it]
可以有很多功能...
\\\
公共功能Foo（ByVal abyt（）As Byte）As Byte
返回& H40
结束功能
///
SCNR
-
Herfried K. Wagner [MVP]
< URL：http：//dotnet.mvps.org/>
There can be many functions...
\\\
Public Function Foo(ByVal abyt() As Byte) As Byte
Return &H40
End Function
///
SCNR
--
Herfried K. Wagner [MVP]
<URL:http://dotnet.mvps.org/>
Hi Herfried
当我正在煮咖啡时，我发现了自己的错误（在帖子中）。它应该是
< code>
Dim ba（1）As Byte
Dim b As Byte
ba（0）=& h34
ba（1）=& h30
b = foo（ba）
< / code>
仍然在寻找foo（），这样b包含& h40。
Charles
" Herfried K. Wagner [MVP]" <喜*************** @ gmx.at>在消息中写道
news：Oc ************* @ TK2MSFTNGP11.phx.gbl ...
Hi Herfried
As I was making coffee I realised my mistake (in the post). It should read
<code>
Dim ba(1) As Byte
Dim b As Byte
ba(0) = &h34
ba(1) = &h30
b = foo(ba)
</code>
Still looking for foo() such that b contains &h40.
Charles
"Herfried K. Wagner [MVP]" <hi***************@gmx.at> wrote in message
news:Oc*************@TK2MSFTNGP11.phx.gbl...
*" Charles Law" < BL *** @ nowhere.com> scripsit：
* "Charles Law" <bl***@nowhere.com> scripsit:
考虑到.NET中丰富的转换功能，我认为这将是直截了当的，但事实证明它比想象的更复杂。
给出以下内容
< code>
Dim ba（1）As Byte
Dim b As Byte
ba（0 ）=& h4
ba（1）=& h0
b = foo（ba）
< / code>
什么是foo（）这样b包含& h40？
TIA
[我可以为此写一个算法，但肯定有一个
简洁转换]
I thought this was going to be straight forward, given the wealth of
conversion functions in .NET, but it is proving more convoluted than
imagined.
Given the following
<code>
Dim ba(1) As Byte
Dim b As Byte
ba(0) = &h4
ba(1) = &h0
b = foo(ba)
</code>
What is foo() such that b contains &h40 ?
TIA
Charles
[I could write an algorithm for this, but there must surely be a succinct conversion for it]
可以有很多功能...
\\\
Public Function Foo（ByVal） abyt（）As Byte）作为Byte
返回&H40
结束功能
///
SCNR
-
Herfried K. Wagner [MVP]
< URL：http：//dotnet.mvps.org/>
There can be many functions...
\\\
Public Function Foo(ByVal abyt() As Byte) As Byte
Return &H40
End Function
///
SCNR
--
Herfried K. Wagner [MVP]
<URL:http://dotnet.mvps.org/>
更正
给出以下
< code>
Dim ba（1）As Byte
Dim b As Byte
ba（0）=& h34
ba（1）=& h30
b = foo（ba）
< / code>
什么是foo（），b包含& h40？
TIA
Charles
" Charles Law" < BL *** @ nowhere.com>在消息中写道
news：uy ************** @ TK2MSFTNGP09.phx.gbl ...
Correction
Given the following
<code>
Dim ba(1) As Byte
Dim b As Byte
ba(0) = &h34
ba(1) = &h30
b = foo(ba)
</code>
What is foo() such that b contains &h40 ?
TIA
Charles
"Charles Law" <bl***@nowhere.com> wrote in message
news:uy**************@TK2MSFTNGP09.phx.gbl...
我以为这是去的为了直截了当，给出了.NET中丰富的转换功能，但事实证明它比想象的更复杂。
给出以下内容
< code>
Dim ba（1）As Byte
Dim b As Byte
ba（0）=& h4
ba（1）=& ; h0
b = foo（ba）
< / code>
什么是foo（），b包含& h40？
TIA
Charles
[我可以为此写一个算法，但肯定会有简洁的转换]
I thought this was going to be straight forward, given the wealth of
conversion functions in .NET, but it is proving more convoluted than
imagined.
Given the following
<code>
Dim ba(1) As Byte
Dim b As Byte
ba(0) = &h4
ba(1) = &h0
b = foo(ba)
</code>
What is foo() such that b contains &h40 ?
TIA
Charles
[I could write an algorithm for this, but there must surely be a succinct
conversion for it]
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