参数处理 [英] Argument Processing
问题描述
您好，
我正在尝试学习如何在C中处理命令行参数。
下面我编写的代码段作为测试程序进行编译，但是当我尝试运行它时，我会尝试运行它，它是核心转储。这是在FreeBSD环境下。
我在这里做错了什么？
/ *
只是echos屏幕上的命令行参数
测试参数处理的格式
* /
#include< ; stdio.h>
#include< string.h>
int main（int argc，char argv []）
{
int i; / *通用计数器* /
printf（" argc =％d"，argc）;
for（i = 0; i< = argc ; i ++）
{
printf（" argv [％d] =％s \ n"，i，argv [i]）;
}
/ *返回操作系统* /
返回（0）;
}
-
Daniel Rudy
电子邮件地址已被编码以减少垃圾邮件。
删除所有号码，然后删除无效，电子邮件，否和垃圾邮件以进行回复。
Hello,
I''m trying to learn how command line arguments are handled in C. The
following code segment that I wrote as a test program compiles, but when
I try to run it, it core dumps. This is under a FreeBSD environment.
What am I doing wrong here?
/*
just echos the command line arguments onto the screen
tests the format of argument processing
*/
#include <stdio.h>
#include <string.h>
int main(int argc, char argv[])
{
int i; /* generic counter */
printf("argc = %d", argc);
for (i = 0; i <= argc; i++)
{
printf("argv[%d] = %s\n", i, argv[i]);
}
/* return to operating system */
return(0);
}
--
Daniel Rudy
Email address has been encoded to reduce spam.
Remove all numbers, then remove invalid, email, no, and spam to reply.
推荐答案
2004年11月5日星期五05:41:31 GMT，Daniel Rudy
< i0 ********************************** @ n0o1p2a3c4b5 e6l7l8s9p0a1m2.3n4e5t6>
在comp.lang.c中写道：
On Fri, 05 Nov 2004 05:41:31 GMT, Daniel Rudy
<i0**********************************@n0o1p2a3c4b5 e6l7l8s9p0a1m2.3n4e5t6>
wrote in comp.lang.c:
你好，
我正在努力学习如何命令行参数在C中处理。我作为测试程序编写的以下代码段编译，但是当我尝试运行它时，它会进行核心转储。这是在FreeBSD环境下。
我在这里做错了什么？
/ *
只需将命令行参数回显到屏幕上
测试参数处理的格式
* /
#include< stdio.h>
#include< string.h>
int main（int argc，char argv []）
{
int i; / *通用计数器* /
printf（" argc =％d"，argc）;
for（i = 0; i< = argc; i ++）
替换< ="用<在循环。 argv [argv]是一个空指针。
{
printf（" argv [％d] =％s \ n"，i，argv [i]）;
}
/ *返回操作系统* /
返回（0）;
注意''return''是一个声明，而不是一个函数。括号不会造成伤害，但自从第一个ANSI标准15年以来没有被要求。
}
Hello,
I''m trying to learn how command line arguments are handled in C. The
following code segment that I wrote as a test program compiles, but when
I try to run it, it core dumps. This is under a FreeBSD environment.
What am I doing wrong here?
/*
just echos the command line arguments onto the screen
tests the format of argument processing
*/
#include <stdio.h>
#include <string.h>
int main(int argc, char argv[])
{
int i; /* generic counter */
printf("argc = %d", argc);
for (i = 0; i <= argc; i++)
Replace "<=" with "<" in the loop. argv[argv] is a null pointer.
{
printf("argv[%d] = %s\n", i, argv[i]);
}
/* return to operating system */
return(0);
Note that ''return'' is a statement, not a function. Parentheses do no
harm, but have not been required since the first ANSI standard 15
years ago.
}
-
Jack Klein
主页： http://JK-Technology.Com
常见问题解答
comp.lang.c http://www.eskimo.com/~scs/C-faq/top。 html
comp.lang.c ++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c ++
http://www.contrib.andrew.cmu.edu/~ a ... FAQ-acllc.html
--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c++
http://www.contrib.andrew.cmu.edu/~a...FAQ-acllc.html
" Daniel Rudy"
< ; i0 ********************************** @ n0o1p2a3c4b5 e6l7l8s9p0a1m2.3n4e5t6>
WRO消息新闻：fo ***************** @ newssvr14.news.prodigy.co m ...
"Daniel Rudy"
<i0**********************************@n0o1p2a3c4b5 e6l7l8s9p0a1m2.3n4e5t6>
wrote in message news:fo*****************@newssvr14.news.prodigy.co m...
你好，
我正在尝试学习如何在C中处理命令行参数。
我作为测试程序编写的代码段编译，但是当我尝试运行时它，核心转储。这是在FreeBSD环境下。
我在这里做错了什么？
/ *
只需将命令行参数回显到屏幕上
测试参数处理的格式
* /
#include< stdio.h>
#include< string.h>
int main（int argc，char argv []）
{
int i; / *通用计数器* /
printf（" argc =％d"，argc）;
for（i = 0; i< = argc; i ++）
{
printf（" argv [％d] =％s \ n"，i，argv [i]）;
}
/ *返回操作系统* /
返回（0）;
}
您从命令行传递给main的是什么？
您可以尝试在第一个printf之前添加它。
if（argc< 3）
{
printf（" main\\\
的参数不足）;
返回0;
}
- Ravi
-
Daniel Rudy
电子邮件地址已被编码以减少垃圾邮件。
删除所有号码，然后删除无效，电子邮件，否和垃圾邮件以进行回复。
Hello,
I''m trying to learn how command line arguments are handled in C. The
following code segment that I wrote as a test program compiles, but when
I try to run it, it core dumps. This is under a FreeBSD environment.
What am I doing wrong here?
/*
just echos the command line arguments onto the screen
tests the format of argument processing
*/
#include <stdio.h>
#include <string.h>
int main(int argc, char argv[])
{
int i; /* generic counter */
printf("argc = %d", argc);
for (i = 0; i <= argc; i++)
{
printf("argv[%d] = %s\n", i, argv[i]);
}
/* return to operating system */
return(0);
}
What are you passing to main from command line ?
You might try adding this before the first printf.
if ( argc < 3 )
{
printf ("Insufficient arguments to main\n");
return 0;
}
- Ravi
--
Daniel Rudy
Email address has been encoded to reduce spam.
Remove all numbers, then remove invalid, email, no, and spam to reply.
Daniel Rudy写道：
Daniel Rudy wrote:
#include< stdio.h>
#include< string.h>
int main（ int argc，char argv []）
{
int i; / *通用计数器* /
printf（" argc =％d"，argc）;
for（i = 0; i< = argc; i ++）
将此重写为
for（i = 0; i< argc; i ++）
{
printf（" argv [ ％d] =％s \ n"，i，argv [i]）;
}
/ *返回操作系统* /
return（0）;
}
#include <stdio.h>
#include <string.h>
int main(int argc, char argv[])
{
int i; /* generic counter */
printf("argc = %d", argc);
for (i = 0; i <= argc; i++)
Rewrite this as
for (i = 0; i < argc; i++)
{
printf("argv[%d] = %s\n", i, argv[i]);
}
/* return to operating system */
return(0);
}
Satyajit
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