这个程序有意义吗？ [英] Does this program make any sense?
问题描述
我用g ++ / gcc 3.3.1和MS Visual C ++
6编译了以下程序。它运行没有任何错误。这件事有意义吗？是某些使用的
还是c / c ++语法/ CFG的一些问题？
#include< stdio.h>
int func（）
{
int x;
返回x，x;
}
int main（）
{
int a，b;
a，b，a;
printf（"％d"，func）;
返回（a，b）;
}
问候，
Rabeeh。
I have compiled following program with g++/gcc 3.3.1 and "MS Visual C++
6" and it ran without any errors. Does this thing make any sense? Is it
of some use or some problem with grammar/CFG of c/c++?
#include <stdio.h>
int func()
{
int x;
return x,x;
}
int main()
{
int a,b;
a,b,a;
printf("%d",func);
return (a,b);
}
Regards,
Rabeeh.
推荐答案
" centurian"写道：
"centurian" wrote:
我用g ++ / gcc 3.3.1和MS Visual C ++
6编译了以下程序。它运行没有任何错误。这件事有意义吗？是否有某些用途或c / c ++语法/ CFG的某些问题？
#include< stdio.h>
int func（）
{
int x;
返回x，x;
}
int main（）
{
int a，b;
a，b，a;
printf（"％d"，func）;
返回（a，b）;
}
I have compiled following program with g++/gcc 3.3.1 and "MS Visual C++
6" and it ran without any errors. Does this thing make any sense? Is it
of some use or some problem with grammar/CFG of c/c++?
#include <stdio.h>
int func()
{
int x;
return x,x;
}
int main()
{
int a,b;
a,b,a;
printf("%d",func);
return (a,b);
}
您确定：
printf（"％d"，func）;
不应该是
printf（"％d"，func（））;
??
如果所以，它是合法的，但它没有任何用处...
John
Are you sure:
printf("%d",func);
shouldn''t be
printf("%d",func());
??
If so, it is legal, but it does not serve any useful purpose...
John
centurian写道：
centurian wrote:
我用g ++ / gcc 3.3.1和MS Visual C ++
6编译了以下程序。它运行没有任何错误。这件事有意义吗？是否有某些用途或c / c ++语法/ CFG的某些问题？
#include< stdio.h>
int func（）
{
int x;
返回x，x;
}
int main（）
{
int a，b;
a，b，a;
printf（"％d"，func）;
返回（a，b）;
}
I have compiled following program with g++/gcc 3.3.1 and "MS Visual C++
6" and it ran without any errors. Does this thing make any sense? Is it
of some use or some problem with grammar/CFG of c/c++?
#include <stdio.h>
int func()
{
int x;
return x,x;
}
int main()
{
int a,b;
a,b,a;
printf("%d",func);
return (a,b);
}
阅读逗号操作员。
- J.
Read up on "comma operator".
- J.
文章< 11 ** ********************@f14g2000cwb.googlegroups .com> ;,
" centurian" < RA *********** @ gmail.com>写道：
In article <11**********************@f14g2000cwb.googlegroups .com>,
"centurian" <ra***********@gmail.com> wrote:
我用g ++ / gcc 3.3.1和MS Visual C ++
6编译了以下程序。它运行没有任何错误。这件事有意义吗？是否有某些用途或c / c ++语法/ CFG的某些问题？
#include< stdio.h>
int func（）
{
int x;
返回x，x;
}
int main（）
{
int a，b;
a，b，a;
printf（"％d"，func）;
返回（a，b）;
}
I have compiled following program with g++/gcc 3.3.1 and "MS Visual C++
6" and it ran without any errors. Does this thing make any sense? Is it
of some use or some problem with grammar/CFG of c/c++?
#include <stdio.h>
int func()
{
int x;
return x,x;
}
int main()
{
int a,b;
a,b,a;
printf("%d",func);
return (a,b);
}
我最近指责某人使用逗号运算符来避免使用'if'语句中的括号
。他做了：
如果（条件）表达式1，表达式2;
我没有留下深刻的印象。
-
魔术取决于传统和信仰。它不欢迎观察，
也不会通过实验获利。另一方面，科学的经验基于
;它可以通过观察和实验进行校正。
I recently berated someone for using the comma operator to avoid braces
in an ''if'' statement. He did:
if ( condition ) expression1, expression2;
I was not impressed.
--
Magic depends on tradition and belief. It does not welcome observation,
nor does it profit by experiment. On the other hand, science is based
on experience; it is open to correction by observation and experiment.
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