乘以7 [英] multiplication by 7

问题描述

快速将数字乘以7

give a fast way to multiply a number by 7

推荐答案

sudharsan写道：

sudharsan wrote:

give快速将数字乘以7

give a fast way to multiply a number by 7

int n = 1;


n * = 7; //在我的系统上只有几个时钟！

-

==============

*不是学究者*

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int n = 1;

n *= 7; // Just a few clocks on my system!
--
==============
*Not a pedant*
==============

sudharsan写道：

sudharsan wrote:

给出一个快速的方法将数字乘以7

give a fast way to multiply a number by 7

想一想：

x * 7 = x *（4 + 2 + 1）


这与C有什么关系？


-

BR，Vladimir

Think along the lines of:

x*7 = x*(4+2+1)

How is this related to C?

--
BR, Vladimir

Vladimir S. Oka写道：

Vladimir S. Oka wrote:

sudharsan写道：

sudharsan wrote:

快速将数字乘以7

按以下方式思考：

x * 7 = x *（4 + 2 + 1）

这与C有什么关系？

Think along the lines of:

x*7 = x*(4+2+1)

How is this related to C?

大多数C编译器都知道生成的代码之间的合理折衷

目标架构的大小和速度。

Most C compilers know a reasonable compromise between generated code
size and speed for their target architecture.

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