Char *问题 [英] Char * question

问题描述

你好，

我的pgm是

main（）

{

char * c;

printf（" \ n c的大小是％d，sizeof（c））;

c ="我是初学者;

printf（" \ n字符串c的大小是％d，sizeof（c））;

}


两者的o / p案件是2

你能回答我为什么吗？

解决方案

smartbeginner说：
< blockquote class =post_quotes>你好，
我的pgm是
main（）
{*> char * c;
printf（" \ n size of c是％d，sizeof（c））;


这是你的第一个问题，与原型有关。请阅读以此消息ID开头的

最近的帖子：


< 11 *************** *******@f14g2000cwb.googlegroups .com>


提出了类似的问题并发生了类似的错误。


另外请注意，sizeof产生size_t，而不是int，因此％d是不合适的。

c =我是初学者;
printf（" \ n字符串c的大小是％d） ，sizeof（c））;
}

两种情况下的o / p都是2
你能回答我为什么吗？

为对象赋值不会改变其大小。


-

Richard Heathfield

" ; Usenet是一个奇怪的地方 - dmr 29/7/1999
http://www.cpax.org.uk

电子邮件：rjh在上面的域名（但显然放弃了www）

char * c;


是一个字符指针;


c =我是初学者;


c的分配怎么样

因为c是一个指针，它总是占用两个字节来保存

地址，因此o / p是2。当你初始化指针c

时，它取字符串的起始地址，因此即使对于

，o / p也是2。

希望我是对的。祝你玩得愉快

Hello,
My pgm is
main()
{
char *c;
printf("\n Size of c is %d",sizeof(c));
c="Im a beginner";
printf("\n Size of string c is %d",sizeof(c));
}

The o/p in both cases is 2
Can you answer me why?

解决方案

smartbeginner said:

Hello,
My pgm is
main()
{
char *c;
printf("\n Size of c is %d",sizeof(c));
Here is your first problem, which is to do with prototypes. Please read a
recent thread which started with this message ID:

<11**********************@f14g2000cwb.googlegroups .com>

which asked a similar question and had a similar error.

Also note that sizeof yields size_t, not int, so %d is inappropriate.
c="Im a beginner";
printf("\n Size of string c is %d",sizeof(c));
}

The o/p in both cases is 2
Can you answer me why?

Assigning a value to an object does not change its size.

--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at above domain (but drop the www, obviously)

char* c;

is a character pointer;

c= "Im a beginner";

what about the allocation of c

since c is a pointer it always occupies two bytes to hold the
address,hence the o/p is 2. when you have initialised the pointer c
,it takes the starting address of string,hence the o/p is two even for
that.
hope i''m correct.have a nice time

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