char 数组 = char 数组的问题 [英] problems with char array = char array

问题描述

我有:

char message1[100];
char message2[100];

当我尝试执行 message1 = message2 时，出现错误:

When I try to do message1 = message2, I get error:

从类型 'char *'

我有类似的功能

if(send(clntSocket, echoBuffer, recvMsgSize, 0) != recvMsgSize){
   DieWithError("send() failed")
}

介于两者之间.这些事情会以某种方式搞砸吗?:(

inbetween. Could these mess things up somehow? :(

我有一种感觉，也许你不能对 char 数组或其他东西执行 =，但我环顾四周，找不到任何东西.

I have a feeling maybe you can't do = on char arrays or something, but I looked around and couldn't find anything.

推荐答案

你的怀疑是正确的.C(我假设这是 C)将数组变量视为指针.

Your suspicions are correct. C (I'm assuming this is C) treats an array variable as a pointer.

您需要阅读有关数组和指针的 C 常见问题解答:http://c-faq.com/aryptr/index.html

You need to read the C FAQ about arrays and pointers: http://c-faq.com/aryptr/index.html

这篇关于char 数组 = char 数组的问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！