将char存储到char数组中. [英] To Store char into char array.

问题描述

你们好..

拜托，帮帮我...！示例代码就是这样..

Hello Guys..

Please, Help me out of this...! The sample code is like this..

int i = 65;
char c = static_cast<char>(i);  // here c stores the letter 'A'.

在我的计划中，每当我重视变化&时，我正在将整数转换为char.但是我的疑问是如何将char存储到字符数组中?

例如:i值为65,66,67，依此类推.正在转换为等效字符，例如"A"，"B"，"C"和等等，而且，我想将这些A，B，C字符存储到Character数组中..

请给我建议一些想法..

谢谢..

In my Program, Every time i value changes & Am converting integer to char. But my doubt is How do i store char into character array ?

For Example: i values are 65,66,67 and so on.. & Am converting into equivalent characters like ''A'',''B'',''C'' & so on.. And, I want to store these A,B,C characters into Character array..

Please suggest me some ideas..

Thanks..

推荐答案

#include <stdio.h>
int main()
{
    const int maxItems = 10;
    char myArray[maxItems], curChar;
    int i;
    for (i=0; i<maxItems; i++)
    {
        curChar = i;
        curChar += 'a';
        myArray[i] = curChar;
    }
    for (i=0; i<maxItems; i++)
    {
        printf("Item %d: '%c'\n", i, myArray[i]);
    }
    return 0;
}

不清楚，
但说明很少:
1.如果要使用数字数据设置字符值，则不需要强制转换
例如

Not Clear,
But few instruction:
1. You do not need casting if you want use numeric data to set character value
e.g.

//all of them are valid statement
char c;
c=65;
c=0x41; 
c='A';
c='A'+32; // you will get 'a'
c='A';
c++;      //you will get 'B'

2.要了解您需要的知识，您需要了解数组.这超出了这里的范围.

2. To understand you need you need to learn about array. It is beyond scope here.

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