将 char 数组从 c++ 传递到 fortran [英] passing char arrays from c++ to fortran

问题描述

我在将 char 数组从 c++ 传递到 fortran (f90) 时遇到问题.

I am having trouble passing char arrays from c++ to fortran (f90).

这是我的 c++ 文件，'cmain.cxx':

Here is my c++ file, 'cmain.cxx':

#include <iostream>

using namespace std;

extern "C" int ftest_( char (*string)[4] );

int main() {
    char string[2][4];

    strcpy(string[0],"abc");
    strcpy(string[1],"xyz");

    cout << "c++: string[0] = '" << string[0] << "'" << endl;
    cout << "c++: string[1] = '" << string[1] << "'" << endl;

    ftest_(string);

    return 0;
}

这是我的 fortran 文件，'ftest.f90':

Here is my fortran file, 'ftest.f90':

SUBROUTINE FTEST(string)

CHARACTER*3 string(2)
CHARACTER*3 expected(2)
data expected(1)/'abc'/
data expected(2)/'xyz'/

DO i=1,2
    WRITE(6,10) i,string(i)
10  FORMAT("fortran: string(",i1,") = '", a, "'" )

    IF(string(i).eq.expected(i)) THEN
        WRITE(6,20) string(i),expected(i)
20      FORMAT("'",a,"' equals '",a,"'")
    ELSE
        WRITE(6,30) string(i),expected(i)
30      FORMAT("'",a,"' does not equal '",a,"'")
    END IF
ENDDO

RETURN
END

构建过程是:

gfortran -c -m64   ftest.f90 
g++ -c  cmain.cxx
gfortran -m64 -lstdc++ -gnofor_main -o test ftest.o cmain.o

请注意，可执行文件也可以通过以下方式构建:

note that the executable can also be build via:

g++ -lgfortran -o test ftest.o cmain.o

另外，当我运行 OSX 10.6 时，需要 -m64 标志.

Also, the -m64 flag is required as I am running OSX 10.6.

执行'test'的输出是:

The output from executing 'test' is:

c++: string[0] = 'abc'
c++: string[1] = 'xyz'
fortran: string(1) = 'abc'
'abc' equals 'abc'
fortran: string(2) = 'xy'
'xy' does not equal 'xyz'

在 ftest.f90 中声明大小为 4 的字符串"和预期"字符数组，即:

Declaring the 'string' and 'expected' character arrays in ftest.f90 with size 4, ie:

CHARACTER*4 string(2)
CHARACTER*4 expected(2)

重新编译会得到以下输出:

and recompiling gives the following output:

c++: string[0] = 'abc'
c++: string[1] = 'xyz'
fortran: string(1) = 'abc'
'abc' does not equal 'abc '
fortran: string(2) = 'xyz'
'xyz' does not equal 'xyz '

在'cmain.cxx'中声明大小为3的字符数组，即:

Declaring the character arrays in 'cmain.cxx' with size 3, ie:

extern "C" int ftest_( char (*string)[3] );

int main() {
    char string[2][3];

并恢复到fortran文件中的原始大小(3)，即:

and reverting to the original size in the fortran file (3), ie:

CHARACTER*3 string(2)
CHARACTER*3 expected(2)

重新编译会得到以下输出:

and recompiling gives the following output:

c++: string[0] = 'abcxyz'
c++: string[1] = 'xyz'
fortran: string(1) = 'abc'
'abc' equals 'abc'
fortran: string(2) = 'xyz'
'xyz' equals 'xyz'

所以最后一种情况是唯一可行的，但在这里我将 3 个字符分配给大小为 3 的 char 数组，这意味着缺少终止的 ''，并导致 'abcxyz' 输出 - 这是我的预期应用程序不可接受.

So the last case is the only one that works, but here I have assigned 3 characters to a char array of size 3 which means the terminating '' is missing, and leads to the 'abcxyz' output - this is not acceptable for my intended application.

任何帮助将不胜感激，这让我发疯了！

Any help would be greatly appreciated, this is driving me nuts!

推荐答案

C 字符串以零结尾，而 fortran 字符串按照惯例是用空格填充的，但大小固定.您不应该期望能够在不进行一些转换的情况下将 C 字符串传递给 fortran.

C strings are zero terminated whereas fortran strings, by convention, are space padded but of fixed size. You shouldn't expect to be able to pass C strings to fortran without some conversion.

例如:

#include <algorithm>

void ConvertToFortran(char* fstring, std::size_t fstring_len,
                      const char* cstring)
{
    std::size_t inlen = std::strlen(cstring);
    std::size_t cpylen = std::min(inlen, fstring_len);

    if (inlen > fstring_len)
    {
        // TODO: truncation error or warning
    }

    std::copy(cstring, cstring + cpylen, fstring);
    std::fill(fstring + cpylen, fstring + fstring_len, ' ');
}

然后您可以将其与 ftest 的 3 或 4 长度版本一起使用:

Which you can then use with either the 3 or 4 length version of ftest:

#include <iostream>
#include <ostream>
extern "C" int ftest_( char string[][4] );

void ConvertToFortran(char* fstring, std::size_t fstring_len,
                      const char* cstring);

int main()
{
    char cstring[2][4] = { "abc", "xyz" };
    char string[2][4];

    ConvertToFortran(string[0], sizeof string[0], cstring[0]);
    ConvertToFortran(string[1], sizeof string[1], cstring[1]);

    std::cout << "c++: string[0] = '" << cstring[0] << "'" << std::endl;
    std::cout << "c++: string[1] = '" << cstring[1] << "'" << std::endl;

    ftest_(string);

    return 0;
}

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