C ++将char数组传递给函数 [英] C++ passing char array to function

问题描述

我宁愿只使用字符串，但我们不应该那样做，因为老师讨厌它们，并希望我们找出避免它们的方法。因此，我研究了使用结构，但本书并不遥远，当我跳过时，她讨厌它。所以我正在考虑这样做：

I would rather just use a string, but we aren't supposed to as the teacher hates them and wants us to figure out ways to avoid them. So I looked into using a struct, but we aren't that far in the book and she hates it when I skip ahead. So I was thinking of doing this:

#include <iomanip>
#include <iostream>
#include <stdio.h>

using namespace std;

void myfunc(char& );

int main()
{
    char myname[12];
    cout<<"enter  a name ";
    cin>>myname;
    cout<<"myname is "<<myname;

    cout<<"myname is " << myfunc(myname);

    getchar();
    getchar();
    return 0;
}

void myfunc(char &myname1)
{
    myname1 = "Billy"
}

但这不起作用，我也不知道为什么。

But this doesn't work and I don't know why.

推荐答案

一种方法是这样：

void myfunc(char *myname1)
{
    strcpy(myname1,"Billy");
}   

您还需要将main更改为：

You will also need to change your main to:

myfunc(myname);
cout<<"myname is " << myname;

但是您必须注意不要溢出初始缓冲区。

However you have to be careful not to overflow your initial buffer.

原始代码不起作用的原因是，您无法将字符串分配给 char 指针。相反，您必须将字符串复制到 char * 。

The reason why your original code doesn't work is because you can't assign strings to char pointers. Instead you must copy the string to the char*.

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