C ++ Primer ex 7.3 [英] C++ Primer ex 7.3
问题描述
我想知道这是不是一个很好的设计风格（据我所知，直到chpater 7获得了
）：
/ * C ++入门 - 4 / e
*
*练习7.4
*声明
*写一个程序拿两个int paramaters并生成
将第一个提升到第二个幂的结果。写一个
程序来调用你的函数传递两个整数。验证
结果。
*
* /
#include< iostream>
int raise_power（int x，int y）
{
int mult = 1;
while（y）
{
mult = mult * x;
--y;
}
返回mult;
}
int main（）
{
int i = 2;
int j = 3;
int mult_result = 8;
std :: cout<< static_cast< bool>（mult_result == raise_power（i，j））
<< std :: endl;
/ *好，从未转换为真，它仍然是1 :( * /
返回0;
}
-
http://arnuld.blogspot.com
i wanted to know if that''s a good design style (upto the knowledge i have
gained till chpater 7):
/* C++ Primer - 4/e
*
* exercise 7.4
* STATEMENT
* write a programme to take two int paramaters and generate the
result of raising the first to the power of the second. write a
programme to call your function passing it two ints. verify the
result.
*
*/
#include <iostream>
int raise_power(int x, int y)
{
int mult = 1;
while( y )
{
mult = mult * x;
--y;
}
return mult;
}
int main()
{
int i = 2;
int j = 3;
int mult_result = 8;
std::cout << static_cast<bool>(mult_result == raise_power(i, j))
<< std::endl;
/* well, never got converted to "true", it alwasy remains 1 :( */
return 0;
}
--
http://arnuld.blogspot.com
推荐答案
8月8日晚上9:59，arnuld < geek.arn ... @ gmail.comwrote：
On Aug 8, 9:59 pm, arnuld <geek.arn...@gmail.comwrote:
i想知道这是不是一个好的设计风格（取决于我的知识
获得直到chpater 7）：
/ * C ++ Primer - 4 / e
*
*练习7.4
*语句
*编写一个程序来获取两个int参数并生成
结果，将第一个提升到第二个幂。写一个
程序来调用你的函数传递两个整数。验证
结果。
*
* /
#include< iostream>
int raise_power（int x，int y）
i wanted to know if that''s a good design style (upto the knowledge i have
gained till chpater 7):
/* C++ Primer - 4/e
*
* exercise 7.4
* STATEMENT
* write a programme to take two int paramaters and generate the
result of raising the first to the power of the second. write a
programme to call your function passing it two ints. verify the
result.
*
*/
#include <iostream>
int raise_power(int x, int y)
我建议使用更有意义的变量名而不是''x''
和'' Y ''。想到''base''和''exponent''。
I would suggest using more meaningful variable names other than ''x''
and ''y''. ''base'' and ''exponent'' come to mind.
{
int mult = 1;
而（y）
{
int mult = 1;
while( y )
如果''y'是负数（由于它被定义为
int），这个条件会导致你的程序出现重大错误。
If ''y'' is a negative number (which is allowed since it''s defined as an
int), this while condition will cause a major bug n your program.
{
mult = mult * x;
--y;
{
mult = mult * x;
--y;
你的状况是错误的。但如果它是正确的，你可以简单地写
而（y--）没有
单机减量就能达到相同的效果。
Your while condition is wrong. But if it was correct, you could have
simply written "while( y-- )" to achieve the same result without the
stand-alone decrement.
}
返回很多;
}
int main（）
{
int i = 2;
int j = 3;
int mult_result = 8;
std :: cout<< static_cast< bool>（mult_result == raise_power（i，j））
<< std :: endl;
/ *好，从未转换为true，它alwasy仍为1 :( * /
返回0;
< br $>
}
--http：//arnuld.blogspot.com
}
return mult;
}
int main()
{
int i = 2;
int j = 3;
int mult_result = 8;
std::cout << static_cast<bool>(mult_result == raise_power(i, j))
<< std::endl;
/* well, never got converted to "true", it alwasy remains 1 :( */
return 0;
}
--http://arnuld.blogspot.com
干杯，
Andre
Cheers,
Andre
arnuld写道：
arnuld wrote:
i想知道是否这是一个很好的设计风格（根据我的知识直到chpater 7获得
）：
/ * C ++ Primer - 4 / e
*
*练习7.4
*语句
*编写一个程序来获取两个int参数并生成
将第一个提升到第二个的力量。写一个
程序来调用你的函数传递两个整数。验证
结果。< br $>
*
* /
#include< iostream>
int raise_power （int x，int y）
{
int mult = 1;
wh ile（y）
{
mult = mult * x;
--y;
}
返回mult;
}
i wanted to know if that''s a good design style (upto the knowledge i have
gained till chpater 7):
/* C++ Primer - 4/e
*
* exercise 7.4
* STATEMENT
* write a programme to take two int paramaters and generate the
result of raising the first to the power of the second. write a
programme to call your function passing it two ints. verify the
result.
*
*/
#include <iostream>
int raise_power(int x, int y)
{
int mult = 1;
while( y )
{
mult = mult * x;
--y;
}
return mult;
}
这对于正数是好的，但是怎么样？否定？
That''s OK for positive numbers, but what about negative?
int main（）
{
int i = 2;
int j = 3;
int mult_result = 8;
std :: cout<< static_cast< bool>（mult_result == raise_power（i，j））
<<的std :: ENDL;
int main()
{
int i = 2;
int j = 3;
int mult_result = 8;
std::cout << static_cast<bool>(mult_result == raise_power(i, j))
<< std::endl;
野蛮，
断言（raise_power（i，j）== mult_result）;
别忘了包括< cassert>
-
Ian Collins。
Be brutal,
assert( raise_power(i, j) == mult_result );
Don''t forget to include <cassert>
--
Ian Collins.
8月9日上午10点14分，Ian Collins< ian-n ... @ hotmail.comwrote：
On Aug 9, 10:14 am, Ian Collins <ian-n...@hotmail.comwrote:
arnuld写道：
arnuld wrote:
... [SNIP] ...
...[SNIP]...
std :: cout<< static_cast< bool>（mult_result == raise_power（i，j））
<<的std :: ENDL;
std::cout << static_cast<bool>(mult_result == raise_power(i, j))
<< std::endl;
野蛮，
断言（raise_power（i，j）== mult_result ）;
别忘了包含< cassert>
Be brutal,
assert( raise_power(i, j) == mult_result );
Don''t forget to include <cassert>
引发错误：
/ home / arnuld / programming / cpp
that raises an error:
/home/arnuld/programming/cpp
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