如何打印短整数？ [英] how to print a short and long integer?
问题描述
短片;
长l;
s = -2;
l = -3;
printf （"％_％_"，s，l）;
格式化字符串中应填写哪些字符用于输出？
Thanx
On Sun，2005年9月25日04:14:29 GMT，a < a@mail.com>写在
comp.lang.c：
short s;
long l;
s = -2;
l = -3;
printf（"％_％_"，s，l）;
在输出的格式化字符串中应填写哪些字符？
Thanx
您的C参考书说什么？
您的编译器的库手册，在线帮助文件或人< br $>
页面告诉你？
为什么你认为usenet可以代替在标准参考文献中查找基本的
信息？
在google.com的搜索框中键入此字符串：
printf" conversion specifiers"
....并按照第一个链接。
-
Jack Klein
主页： http://JK-Technology.Com
$常见问题b $ b comp.lang.c http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c ++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c ++
http://www.contrib.andrew.cmu.edu/~a...FAQ-acllc.html
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a写道：短s;
长l;
s = -2;
l = -3;
printf（"％_％_"，s，l）;
应该在格式化的字符串中填写哪些字符用于输出？
printf（"％d％ld"，s，l）;
printf是一个可变函数，因此它的原型不包含大多数参数的定义
（仅定义了格式字符串参数） 。
因此，对于其他参数，标准促销规则适用：
- - short int promote to int
- - long int保持为long int
每个参数的格式字符串必须预期
参数的格式。 ％d用于int，因此它将用于一个short int，它将
提升为int。 ％ld用于long int。
- -
Lew Pitcher
Master Code代理& JOAT-in-training |可根据要求提供GPG公钥
注册Linux用户＃112576（ http：/ /counter.li.org/ ）
Slackware - 因为我知道我在做什么。
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= Djbp
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a写道：短s;
long l;
s = -2;
l = -3;
printf（"％_％_"，s，l）;
格式化字符串中应填写哪些字符用于输出？
Thanx
#include< stdio.h>
int main（无效）
{
短s = -2;
长l = -3;
printf（"标准方式使用\'%% hd %% ld \"：％hd％ld \ n"，s，l ）;
printf（" （但是\%% d %% ld \应该也能正常工作：％d％ld \ n"，s，l）;
返回0;
}
标准方式使用％hd％ld：-2 -3
（但％d％ld应该也能正常工作：-2 -3
short s;
long l;
s= -2;
l= -3;
printf("% _ %_",s, l);
What characters should be filled out in the formatted string for output?
Thanx
On Sun, 25 Sep 2005 04:14:29 GMT, "a" <a@mail.com> wrote in
comp.lang.c:
short s;
long l;
s= -2;
l= -3;
printf("% _ %_",s, l);
What characters should be filled out in the formatted string for output?
Thanx
What does your C reference book say?
What does your compiler''s library manual, online help file, or man
pages tell you?
Why do you think usenet is a substitute for looking up basic
information in standard references?
Type this string into the search box at google.com:
printf "conversion specifiers"
....and follow the first link.
--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c++
http://www.contrib.andrew.cmu.edu/~a...FAQ-acllc.html
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a wrote:short s;
long l;
s= -2;
l= -3;
printf("% _ %_",s, l);
What characters should be filled out in the formatted string for output?
printf("%d %ld",s,l);
printf is a variadic function, so it''s prototype does not include definitions
for most of it''s arguments (only the format string argument is defined).
Thus, for the other arguments, the standard promotion rules apply:
- - short int promotes to int
- - long int stays as long int
The format strings for each argument must anticipate the format of the
arguments. %d is used for int, so it will be used for a short int which gets
promoted to int. %ld is used for long int.
- --
Lew Pitcher
Master Codewright & JOAT-in-training | GPG public key available on request
Registered Linux User #112576 (http://counter.li.org/)
Slackware - Because I know what I''m doing.
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6moAzVtg16kHNGrjWNmua7A=
=Djbp
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a wrote:short s;
long l;
s= -2;
l= -3;
printf("% _ %_",s, l);
What characters should be filled out in the formatted string for output?
Thanx
#include <stdio.h>
int main(void)
{
short s = -2;
long l = -3;
printf("The standard way using \"%%hd %%ld\": %hd %ld\n", s, l);
printf(" (but \"%%d %%ld\" should work as well: %d %ld\n", s, l);
return 0;
}
The standard way using "%hd %ld": -2 -3
(but "%d %ld" should work as well: -2 -3
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