如何将字符值分配给整数变量？并以整数格式打印。 [英] How to assign character values into integer variables ? and print it in integer format.

问题描述

#include< stdio.h>

void main（）

{

char ch1 ='1';

char ch2 ='5';

int n;

//我想将值15分配给整数变量'n'

---------------------------------------------;

printf（转换后n是％d，n）;

getch（）;

}



我尝试过：



所需输出为：转换后n为15

#include<stdio.h>
void main()
{
char ch1='1';
char ch2='5';
int n;
// i want to assign value 15 into integer variable 'n'
---------------------------------------------;
printf("after convertion n is %d",n);
getch();
}

What I have tried:

required output is : after convertion n is 15

推荐答案

从单个角色来看，它有点复杂 - 你基本上必须自己做：

From individual characters it's a little complex - you will basically have to do it yourself:

char ch1='1';
char ch2='5';
int n;
n = (ch1 - '0') * 10 + (ch2 - '0');
printf("%d\n", n);

但通常情况下，这种转换是使用标准函数从一串字符（一个char值数组）完成的： C库函数 - sscanf（） [ ^ ]

But normally, such conversions are done from a string of characters (an array of char values) using standard functions: C library function - sscanf()[^]

您也可以从 char 数组开始，并使用标准C函数从中获取整数字符数组：

You could also start from a char array and use the standard C function to get an integer from a character array:

char chars[3] = { ch1, ch2, '\0' };
n = atoi(chars);

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