如何将字符值分配给 C 中的整数类型变量? [英] How can you assign a character value to a integer type variable in C?

问题描述

在 C 中，

...
int num = 'a';
...

我的问题很简单.如何在 C 语言中将 '0'、'a'、'b' 等字符分配给整数类型变量而不会出现任何类型错误?

My question is simple. How can you assign a character such as '0', 'a', 'b' to an integer type variable without getting any type error in C language?

推荐答案

由于历史原因(大部分)，字符常量在 C 中属于 int 类型.

For historical reasons (mostly), character constants are of type int in C.

但即使它们不是，像这样的初始化

But even if they weren't, an initialization like

int num = 'a';

或类似的作业

num = 'a';

仍然是完全合法的.任何数字类型的值都可以分配给任何(其他)数字类型的变量，并且该值将被隐式转换(这可能涉及表示形式的更改和/或溢出的风险).

would still be perfectly legal. A value of any numeric type may be assigned to a variable of any (other) numeric type, and the value will be implicitly converted (which may involve a change of representation and/or a risk of overflow).

而char，连同它的亲属unsigned char和signed char，都是数字类型，特别是整数类型.

And char, along with its relatives unsigned char and signed char, are numeric types, specifically integer types.

这篇关于如何将字符值分配给 C 中的整数类型变量?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！