固定的整数打印位数（例如：0001到0100） [英] Fixed number of digits printing of integers (ex: 0001 to 0100)
问题描述
我想不出一个简单的方法来打印具有固定数量
位数的整数，以获得类似0001的1和0100的100
自动只需在变量中指定所需的
位数。
我考虑使用例如％4d打印到变量然后
将''''替换为''''，但我不知道我是否可以打印到阵列，并且
然后我不认为我可以在％和d之间放一个变量来指定我想要的
位数。
我想也许会有一些已经存在且容易方式
这样做我不知道，否则我想知道人们通常如何处理这个问题，谢谢
Michel Rouzicaécrit：我想不出一个用修复打印整数的简单方法的数量/>数字，以便通过在变量中指定所需的
数字来自动获得类似0001 for 1和0100 for 100
的东西。
我考虑过打印使用例如％4d的变量然后
将''''替换为''0''，但我不知道我是否可以打印到阵列，然后我不知道我想我可以在％和d之间加一个变量来指定我想要的数字位数。
我想也许会有一些已存在且简单的方法
这样做我不知道，否则我想知道人们通常如何处理这个问题，谢谢
＃ include< stdio.h>
int main（void）
{
for（int i = 4; i< 10; i ++）
printf（"％05d \ n"，i * 100）;
int width = 6;
printf（"％0 * d \ n"，width，746）;
}
输出
00400
00500
00600
00700
00800
00900
000746
" Michel Rouzic" <弥******** @ yahoo.fr>在消息中写道
news：11 ********************** @ g44g2000cwa.googlegr oups.com ...我不能想到一个简单的方法来打印具有固定数量的
数字的整数，以便通过指定自动获得类似0001 for 1和0100 for 100
的内容变量所需数字的数量。
我考虑使用例如％4d打印到变量然后
将''''替换为''0''，但是我不知道我是否可以打印到数组，然后我不认为我可以在％和d之间加一个变量来指定我想要的数字位数。 br />
我想也许会有一些已经存在且简单的方法来做我不知道的事情，否则我想知道人们是怎样的
通常处理这个问题，谢谢
#include< stdio.h>
int main（）
{
int i = 0;
i $ 1; i< 101; ++ i）
printf（"％04d \ n"，i）;
返回0;
}
你的教科书在哪里？
-Mike
Michel Rouzic写道：我想不出一个简单的方法来打印整数修复
数字的数量，以便通过在变量中指定所需的
数字来自动获得类似0001 for 1和0100 for 100
的内容。
我考虑使用例如％4d打印到变量然后
将''''替换为''0''，但我不知道我是否可以打印到数组，并且
然后我不认为我可以在％和d之间加一个变量来指定我想要的数字位数。
我想也许会有一些已经存在且容易的这样做我不知道的，否则我想知道人们是怎样的>通常处理这个问题，谢谢
尝试％04d
-David
I can''t think of a simple way to print integers with a fix number of
digits, in order to obtain something like 0001 for 1 and 0100 for 100
automatically just by specifying in a variable the number of desired
digits.
I thought about printing to a variable using for example %4d and then
replace '' '' by ''0'', but I don''t know if i can print to an array, and
then I don''t think I can put a variable between % and d to specify the
number of digits I want.
I thought that maybe there would be some already existing and easy way
to do it that I don''t know of, otherwise i''d like to know how people
usually deal with that problem, thanks
Michel Rouzic a écrit :I can''t think of a simple way to print integers with a fix number of
digits, in order to obtain something like 0001 for 1 and 0100 for 100
automatically just by specifying in a variable the number of desired
digits.
I thought about printing to a variable using for example %4d and then
replace '' '' by ''0'', but I don''t know if i can print to an array, and
then I don''t think I can put a variable between % and d to specify the
number of digits I want.
I thought that maybe there would be some already existing and easy way
to do it that I don''t know of, otherwise i''d like to know how people
usually deal with that problem, thanks
#include <stdio.h>
int main(void)
{
for (int i=4; i<10;i++)
printf("%05d\n",i*100);
int width=6;
printf("%0*d\n",width,746);
}
Output
00400
00500
00600
00700
00800
00900
000746
"Michel Rouzic" <Mi********@yahoo.fr> wrote in message
news:11**********************@g44g2000cwa.googlegr oups.com...I can''t think of a simple way to print integers with a fix number of
digits, in order to obtain something like 0001 for 1 and 0100 for 100
automatically just by specifying in a variable the number of desired
digits.
I thought about printing to a variable using for example %4d and then
replace '' '' by ''0'', but I don''t know if i can print to an array, and
then I don''t think I can put a variable between % and d to specify the
number of digits I want.
I thought that maybe there would be some already existing and easy way
to do it that I don''t know of, otherwise i''d like to know how people
usually deal with that problem, thanks
#include <stdio.h>
int main()
{
int i = 0;
for(i = 1; i < 101; ++i)
printf("%04d\n", i);
return 0;
}
Where''s your textbook?
-Mike
Michel Rouzic wrote:I can''t think of a simple way to print integers with a fix number of
digits, in order to obtain something like 0001 for 1 and 0100 for 100
automatically just by specifying in a variable the number of desired
digits.
I thought about printing to a variable using for example %4d and then
replace '' '' by ''0'', but I don''t know if i can print to an array, and
then I don''t think I can put a variable between % and d to specify the
number of digits I want.
I thought that maybe there would be some already existing and easy way
to do it that I don''t know of, otherwise i''d like to know how people
usually deal with that problem, thanks
Try "%04d"
-David
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