gethostbyname（）----删除生成的指针？ [英] gethostbyname() ---- Delete Resulting Pointer?

问题描述

我有以下代码段。在某些平台上，删除

调用在Linux上可以在删除

调用时进行核心转储（内存转储）。我是否负责删除分配了gethostbyname

的内存？

struct hostent * lHostInfo;

lHostInfo = gethostbyname（ipHost。 c_str（））;

memcpy（&（lDestAddr.sin_addr），lHostInfo-> h_addr_list [0]，lHostInfo-

I have the following snippet of code. On some platforms, the delete
calls works, on Linux, it core dumps (memory dump) at the delete
call. Am I responsible for deleting the memory that gethostbyname
allocated?

struct hostent *lHostInfo;
lHostInfo = gethostbyname(ipHost.c_str());
memcpy(&(lDestAddr.sin_addr), lHostInfo->h_addr_list[0], lHostInfo-

>长度h_length）;

>h_length);

删除lHostInfo;


我的印象是除非你没有删除任何东西

个人新'它。这种理论在这种情况下是否正确？

delete lHostInfo;

I am under the impression that you don''t delete anything unless you
personally "new''ed" it. Is this theory correct in this situation?

推荐答案

12月6日上午10点36分，aj< a ... @ bookac.comwrote：

On Dec 6, 10:36 am, aj <[e-mail]:

我有以下代码片段。在某些平台上，删除

调用在Linux上可以在删除

调用时进行核心转储（内存转储）。我是否负责删除分配了gethostbyname

的内存？

struct hostent * lHostInfo;

lHostInfo = gethostbyname（ipHost。 c_str（））;

memcpy（&（lDestAddr.sin_addr），lHostInfo-> h_addr_list [0]，lHostInfo-> h_length）;


删除lHostInfo;


我的印象是你不会删除任何东西，除非你个人bb个人新它。这种理论在这种情况下是否正确？

I have the following snippet of code. On some platforms, the delete
calls works, on Linux, it core dumps (memory dump) at the delete
call. Am I responsible for deleting the memory that gethostbyname
allocated?

struct hostent *lHostInfo;
lHostInfo = gethostbyname(ipHost.c_str());
memcpy(&(lDestAddr.sin_addr), lHostInfo->h_addr_list[0], lHostInfo->h_length);

delete lHostInfo;

I am under the impression that you don''t delete anything unless you
personally "new''ed" it. Is this theory correct in this situation?

C语言中没有''new''或''delete''。


gethostbyname不是由C标准定义。


-

Fred Kleinschmdit

There is no ''new'' or ''delete'' in the C language.

gethostbyname is not defined by the C standard.

--
Fred Kleinschmdit

12月6日，1 ：下午36点，aj< a ... @ bookac.comwrote：

On Dec 6, 1:36 pm, aj <[e-mail]:

我有以下代码片段。在某些平台上，删除

调用在Linux上可以在删除

调用时进行核心转储（内存转储）。我是否负责删除分配了gethostbyname

的内存？

struct hostent * lHostInfo;

lHostInfo = gethostbyname（ipHost。 c_str（））;

memcpy（&（lDestAddr.sin_addr），lHostInfo-> h_addr_list [0]，lHostInfo-> h_length）;


删除lHostInfo;


我的印象是你不会删除任何东西，除非你个人bb个人新它。这种理论在这种情况下是否正确？

I have the following snippet of code. On some platforms, the delete
calls works, on Linux, it core dumps (memory dump) at the delete
call. Am I responsible for deleting the memory that gethostbyname
allocated?

struct hostent *lHostInfo;
lHostInfo = gethostbyname(ipHost.c_str());
memcpy(&(lDestAddr.sin_addr), lHostInfo->h_addr_list[0], lHostInfo->h_length);

delete lHostInfo;

I am under the impression that you don''t delete anything unless you
personally "new''ed" it. Is this theory correct in this situation?

对不起，但C没有

- 一个名为delete的关键字，

- a关键字叫做new

- 一个名为gethostbyname的标准函数（）

- 标准结构叫做hostent


我怀疑您正在编写C ++代码（您提及new和

" delete"以及您在示例代码中使用方法调用），这是

comp.lang.c中的偏离主题


您可能想在comp.lang.c中讨论这个主题。


HTH
-

Lew

Sorry, but C does not have
- a keyword called "delete",
- a keyword called "new"
- a standard function called gethostbyname()
- a standard struture called hostent

I suspect that you are writing C++ code (your mention of "new" and
"delete", and your use of method calls in your example code), which is
off-topic in comp.lang.c

You probably want to discuss this topic in comp.lang.c++

HTH
--
Lew

12月6日下午2:14，Lew Pitcher< lpitc ... @ teksavvy .comwrote：

On Dec 6, 2:14 pm, Lew Pitcher <[e-mail]:

12月6日下午1:36，aj< a ... @ bookac.comwrote：

On Dec 6, 1:36 pm, aj <[e-mail]:

我有以下代码片段。在某些平台上，删除

调用在Linux上可以在删除

调用时进行核心转储（内存转储）。我是否负责删除gethostbyname

分配的内存？

I have the following snippet of code. On some platforms, the delete
calls works, on Linux, it core dumps (memory dump) at the delete
call. Am I responsible for deleting the memory that gethostbyname
allocated?

struct hostent * lHostInfo;

lHostInfo = gethostbyname（ipHost.c_str（））;

memcpy（&（lDestAddr.sin_addr），lHostInfo-> h_addr_list [0]，lHostInfo-> h_length）;

struct hostent *lHostInfo;
lHostInfo = gethostbyname(ipHost.c_str());
memcpy(&(lDestAddr.sin_addr), lHostInfo->h_addr_list[0], lHostInfo->h_length);

delete lHostInfo;

delete lHostInfo;

我的印象是你不会删除任何东西，除非你个人bbbb ;它。这种理论在这种情况下是否正确？

I am under the impression that you don''t delete anything unless you
personally "new''ed" it. Is this theory correct in this situation?

很抱歉，但C没有

- 一个名为delete的关键字，

- a关键字叫做new

- 一个名为gethostbyname的标准函数（）

- 标准结构叫做hostent


我怀疑您正在编写C ++代码（您提及new和

" delete"以及您在示例代码中使用方法调用），这是

comp.lang.c中的偏离主题


您可能想在comp.lang.c中讨论这个主题。


HTH
-

Lew

Sorry, but C does not have
- a keyword called "delete",
- a keyword called "new"
- a standard function called gethostbyname()
- a standard struture called hostent

I suspect that you are writing C++ code (your mention of "new" and
"delete", and your use of method calls in your example code), which is
off-topic in comp.lang.c

You probably want to discuss this topic in comp.lang.c++

HTH
--
Lew

像往常一样，你们没有帮助，只是坚持细节​​。


感谢您的帮助。

As usual, you guys are no help, just sticklers for details.

Thanks for the non-help.

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