使用i ++时的评估顺序 [英] Evaluation order when i++ is used
问题描述
在下文中，第二个参数值放在arr2 [2]中。我可以假设第一个也是
放在arr1 [2]而不是arr1 [3]？更一般地说，在C＃中，我在什么时候递增？
int i = 2;
func（out arr1 [i]，out arr2 [i + ]）;
In the following, the second parameter value is put in arr2[2]. Can I assume that the first is also
put in arr1[2] and not arr1[3]? More generally, in C#, at what point is i incremented?
int i=2;
func(out arr1[i], out arr2[i++]);
推荐答案
12月18日下午1:49，Jon < .wrote：
On Dec 18, 1:49 pm, "Jon" <.wrote:
在下文中，第二个参数值放在arr2 [2]中。我可以假设第一个也是
放在arr1 [2]而不是arr1 [3]？更一般地说，在C＃中，我在什么时候递增？
int i = 2;
func（out arr1 [i]，out arr2 [i + ]）;
In the following, the second parameter value is put in arr2[2]. Can I assume that the first is also
put in arr1[2] and not arr1[3]? More generally, in C#, at what point is i incremented?
int i=2;
func(out arr1[i], out arr2[i++]);
首先评估i（对于第一个参数）然后我再次评估
（对于第二个参数）然后i递增。
但是，像这样的代码不会通过任何有价值的代码审查。
这很好，行为是指定的，但它'
可读性方面很糟糕。
Jon
First i is evaluated (for the first argument) then i is evaluated
again (for the second argument) then i is incremented.
However, code like this won''t get past any worthwhile code review.
It''s nice that the behaviour is specified, but it''s awful in terms of
readability.
Jon
谢谢Jon。
出于好奇，我总是在评估之后递增，例如，如果i ++在第一个而不是第二个参数中，那么增量是否仍然发生评价？
Jon
" Jon Skeet [C＃MVP]" < sk *** @ pobox.com写了留言
新闻：3d *************************** ******* @ t1g2000p ra.googlegroups.com ...
12月18日下午1:49，Jon < .wrote：
Thanks Jon.
Out of curiosity, is incrementing i always after evaluation, eg if the i++ is in the first rather
than in the second parameter, does the increment still happen after all evaluations?
Jon
"Jon Skeet [C# MVP]" <sk***@pobox.comwrote in message
news:3d**********************************@t1g2000p ra.googlegroups.com...
On Dec 18, 1:49 pm, "Jon" <.wrote:
在下文中，第二个参数值放在arr2 [2]中。我可以假设第一个是
还是
放入arr1 [2]而不是arr1 [3]？更一般地说，在C＃中，我在什么时候递增？
int i = 2;
func（out arr1 [i]，out arr2 [i + ]）;
In the following, the second parameter value is put in arr2[2]. Can I assume that the first is
also
put in arr1[2] and not arr1[3]? More generally, in C#, at what point is i incremented?
int i=2;
func(out arr1[i], out arr2[i++]);
首先评估i（对于第一个参数）然后我再次评估
（对于第二个参数）然后i递增。
但是，像这样的代码不会通过任何有价值的代码审查。
这很好，行为是指定的，但它'
可读性方面很糟糕。
Jon
First i is evaluated (for the first argument) then i is evaluated
again (for the second argument) then i is incremented.
However, code like this won''t get past any worthwhile code review.
It''s nice that the behaviour is specified, but it''s awful in terms of
readability.
Jon
-
Ignacio Machin
http：// www.laceupsolutions.com
手机&仓库解决方案。
" Jon" < .wrote in message news：OR **************** @ TK2MSFTNGP04.phx.gbl ...
Hi,
--
Ignacio Machin
http://www.laceupsolutions.com
Mobile & warehouse Solutions.
"Jon" <.wrote in message news:OR****************@TK2MSFTNGP04.phx.gbl...
谢谢Jon。
出于好奇，我总是在评估后递增，例如，如果i ++
在第一个而不是
比第二个参数，在所有
评估之后，增量是否仍然发生？
Thanks Jon.
Out of curiosity, is incrementing i always after evaluation, eg if the i++
is in the first rather
than in the second parameter, does the increment still happen after all
evaluations?
AFAIK是的。
现在一个更有趣的问题是如果不使用
$ b会发生什么$ b评估后你使用之前评估运算符（++ i）并且做
类似于：
func（out arr1 [++ i]， out arr2 [++ i]）
再一次，我和Jon一致，这是一个可怕的代码！
AFAIK yes.
Now a more interesting question is what happens if instead of using the
after evaluation you use the before evaluation operator ( ++i) and do
something like :
func(out arr1[++i], out arr2[++i])
Again, I coincide with Jon, that is an horrible code!
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