如何获得小数位数nr [英] how to get nr of fraction digits
问题描述
您好，
有人知道如何获得小数位数的简单方法吗？
示例：
1.23会得到2
1.234会得到3
的结果是
我知道我可以拆分小数分隔符上的数字，然后计算结果数组的第二部分中的
字符，但我想，那么
应该是另一种解决方案吗？
任务应该很简单，但我正在寻找各种系统数学
课程，但我没有看到它...
或者我应该选择拆分方法吗？ :-)
问候
米歇尔
什么可以更简单比< variable> .ToString.Split（"。" c）（1）.Length？
是什么让你认为应该有另一种解决方案？
" Michel Posseth [MCP]" < Mi ************** @ discuss.microsoft.com写在
消息新闻：62 ************** ******************** @ microsof t.com ...
您好，
有人知道如何获得小数位数的简单方法
？
例如：
1.23将得到2
1.234将得到3的结果
是
我知道我可以在小数分隔符上拆分数字，然后在结果数组的第二部分中计算
字符，但我想，
那里
应该是另一种解决方案吗？
任务应该很简单，但我正在寻找各种系统数学
课程，但我没有看到它...
或我应该去分裂方法？ :-)
问候
米歇尔
< blockquote> Hello Stephany，
well
Dim decval As Decimal = CDec（1.23）
MsgBox（decval.ToString.Split（CChar（System.Globaliz ation.NumberFormatInfo.CurrentInfo.NumberDecimalSe parator））（1）.Length（））
工作正常但我应该还要检查可能发生的异常
i只是认为这种看似有内置的方法通常是b $ b和简单。任务
Michel Posseth
" Stephany Young"写道：
什么可能比< variable> .ToString.Split（"。" c）（1）.Length？
<更简单br />
是什么让你认为应该有另一种解决方案？
Michel Posseth [MCP]" < Mi ************** @ discuss.microsoft.com写在
消息新闻：62 ************** ******************** @ microsof t.com ...
您好，
有人知道如何获得小数位数的简单方法
？
例如：
1.23会得到2
1.234会得到3
的结果是
我知道我可以分割数字在小数分隔符上，然后在结果数组的第二部分中计算
字符，但我想，
有
应该是另一个解决方案吗？
任务应该很简单，但我正在寻找各种系统数学
课程，但我是没有看到它...
或者我应该选择拆分方法吗？ :-)
问候
米歇尔
< blockquote>没有人？
没有人知道不同的做法吗？
" Michel Posseth [MCP]" < Mi ************** @ discussion.microsoft.comschre ef
bericht新闻：87 ************* ********************* @ microsof t.com ...
Hello Stephany，
well
Dim decval As Decimal = CDec（1.23）
MsgBox（decval.ToString。拆分（CChar（System.Globaliz ation.NumberFormatInfo.CurrentInfo.NumberDecimalSe parator））（1）.Length（））
工作正常，但我也应检查可能发生的异常
i只是觉得这个貌似会有一个内置的方法，而且简单是简单的。任务
Michel Posseth
" Stephany Young"写道：
>什么可能比< variable> .ToString.Split（"。" c）（1）.Length更简单？
是什么让你认为应该有另一种解决方案？
Michel Posseth [MCP]" < Mi ************** @ discussion.microsoft.comwrote
在消息新闻中：62 ************** ******************** @ microsof t.com ...
您好，
有人知道如何获得nr分数的简单方法
位数
？
例如：
1.23会得到2
1.234会得到3
是
我知道我可以在小数分隔符上拆分数字，然后在结果数组的第二部分中计算
字符
字符，但我想， ，
那里
应该是另一种解决方案？
任务应该很简单，但我正在寻找各种系统数学
班级，但我没有看到它......
或者我应该选择拆分方法吗？ :-)
问候
米歇尔
Hello ,
Does someone knows a simple way of how to get the nr of fraction digits ?
example :
1.23 would give a result of 2
1.234 would give a result of 3
Yes
I know i could split the number on the decimal seperator and then count the
characters in the second part of the resulting array , but i thought ,, there
should be another solution ?
the task should be simple but i am looking in all sorts of system math
classes but i am not seeing it ...
or should i go for the split method ? :-)
regards
Michel
What could be simpler than <variable>.ToString.Split("."c)(1).Length?
What makes you think that there ''should'' be another solution?
"Michel Posseth [MCP]" <Mi**************@discussions.microsoft.comwrote in
message news:62**********************************@microsof t.com...Hello ,
Does someone knows a simple way of how to get the nr of fraction digits
?
example :
1.23 would give a result of 2
1.234 would give a result of 3
Yes
I know i could split the number on the decimal seperator and then count
the
characters in the second part of the resulting array , but i thought ,,
there
should be another solution ?
the task should be simple but i am looking in all sorts of system math
classes but i am not seeing it ...
or should i go for the split method ? :-)
regards
Michel
Hello Stephany ,
well
Dim decval As Decimal = CDec(1.23)
MsgBox(decval.ToString.Split(CChar(System.Globaliz ation.NumberFormatInfo.CurrentInfo.NumberDecimalSe parator))(1).Length())
works fine however , i should also check for exceptions that might occur
i just thought that there would be a built in method for this seemingly
common and "simple" task
Michel Posseth
"Stephany Young" wrote:
What could be simpler than <variable>.ToString.Split("."c)(1).Length?
What makes you think that there ''should'' be another solution?
"Michel Posseth [MCP]" <Mi**************@discussions.microsoft.comwrote in
message news:62**********************************@microsof t.com...Hello ,
Does someone knows a simple way of how to get the nr of fraction digits
?
example :
1.23 would give a result of 2
1.234 would give a result of 3
Yes
I know i could split the number on the decimal seperator and then count
the
characters in the second part of the resulting array , but i thought ,,
there
should be another solution ?
the task should be simple but i am looking in all sorts of system math
classes but i am not seeing it ...
or should i go for the split method ? :-)
regards
Michel
Nobody ??
Nobody who knows a different way of doing this ?
"Michel Posseth [MCP]" <Mi**************@discussions.microsoft.comschre ef
in bericht news:87**********************************@microsof t.com...Hello Stephany ,
well
Dim decval As Decimal = CDec(1.23)
MsgBox(decval.ToString.Split(CChar(System.Globaliz ation.NumberFormatInfo.CurrentInfo.NumberDecimalSe parator))(1).Length())
works fine however , i should also check for exceptions that might occur
i just thought that there would be a built in method for this seemingly
common and "simple" task
Michel Posseth
"Stephany Young" wrote:
>What could be simpler than <variable>.ToString.Split("."c)(1).Length?
What makes you think that there ''should'' be another solution?
"Michel Posseth [MCP]" <Mi**************@discussions.microsoft.comwrote
in
message news:62**********************************@microsof t.com...Hello ,
Does someone knows a simple way of how to get the nr of fraction
digits
?
example :
1.23 would give a result of 2
1.234 would give a result of 3
Yes
I know i could split the number on the decimal seperator and then count
the
characters in the second part of the resulting array , but i thought ,,
there
should be another solution ?
the task should be simple but i am looking in all sorts of system math
classes but i am not seeing it ...
or should i go for the split method ? :-)
regards
Michel
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