打印小数位数 [英] to print a fractional digits

问题描述

希望单独打印一个小数位，并且在不使用类型转换的情况下，有多少小数位于浮点数中。

例如：你应该在ur pgm中有这个语句：float f = 345.876;

然后输出应该是

o / p：8 7 6和3

我需要的算法适用于所有浮点数

want to print a fractional digits seperately and how many fractionals are in floating point numbers without using typecast..
eg: u should have this statement in ur pgm : float f=345.876;
then output should be
o/p:8 7 6 and 3
the algorithm i need which is working for all floating numbers

推荐答案

这样的东西可能适合你（可能想要清理它）;

Something like this might work for you (might want to clean it up);

#include <stdio.h>
#include <string.h>

int main()
{
    char result[128];
    char buffer[128];
    float f = 345.876f;
    sprintf(buffer,"%f",f);

    int count = 0;
    int r = 0;
    int found_point = 0;
    for(int i = 0; i < 128 && buffer[i] != 0; ++i) {
        if (found_point) {
            result[r] = buffer[i];
            result[++r] = ' ';
            result[++r] = 0;
            ++count;
        }
        else {
            found_point = buffer[i] == '.' ? 1 : 0;
        }
    }

    if (count > 0) {
        strcpy(result + r, "and ");
        char c_buffer[128];
        sprintf(c_buffer, "%d", count);
        strcpy(result + strlen(result), c_buffer);
    }

    printf("o/p: %s\r\n", result);

    return 0;
}

希望这会有所帮助，

Fredrik

Hope this helps,
Fredrik

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