验证表单输入数据 [英] Validating form input data

问题描述

大家好，


我想用一种优雅的方式处理一些来自表格的输入数据。当用户点击提交按钮时，我希望表格再次出现，并且已填入已输入的有效数据并提示

用户重新输入输入无效数据。如果所有数据都有效，我将转发到另一个.php页面，该页面将数据输入数据库。


我试图在以下方式：表单总是回击

本身，但是当所有数据都有效时，我使用PHP：header（）重定向到执行的

data.php数据库插入。问题是数据

不能用于$ _POST变量中的data.php。我怎样才能克服这个问题？
问题？处理整个事情的任何其他微妙方式？任何帮助

赞赏。

Hello everyone,

I am tying to come up with an elegant way to process some input data that
come from a form. When the user hits the ''Submit'' button, i want the form to
appear again with the already entered valid data filled in and prompt the
user to re-enter the non-valid data. If all data is valid, i will forward to
an other .php page which enters the data into a database.

I tried to do this in the following way: the form always hits back on
itself, but when all data is valid i use the PHP:header() to redirect to the
data.php that performs the database insertion. The problem is that the data
is not available to data.php in the $_POST variable. How can i overcome this
problem? Any other subtle way to handle the whole thing? Any help
appreciated.

推荐答案

_POST变量。我怎样才能克服这个问题？
问题？处理整个事情的任何其他微妙方式？任何帮助

赞赏。

_POST variable. How can i overcome this
problem? Any other subtle way to handle the whole thing? Any help
appreciated.

stathis gotsis写道：

stathis gotsis wrote:

大家好，

我想要提出一种优雅的方法来处理来自表单的输入数据。当用户点击提交按钮时，我希望表格再次出现，并填写已输入的有效数据，并提示
用户重新输入无效数据。如果所有数据都有效，我将转发到另一个.php页面，该页面将数据输入数据库。

我尝试按以下方式执行此操作：表单始终返回
本身，但是当所有数据都有效时，我使用PHP：header（）重定向到执行数据库插入的
data.php。问题是

Hello everyone,

I am tying to come up with an elegant way to process some input data that
come from a form. When the user hits the ''Submit'' button, i want the form to
appear again with the already entered valid data filled in and prompt the
user to re-enter the non-valid data. If all data is valid, i will forward to
an other .php page which enters the data into a database.

I tried to do this in the following way: the form always hits back on
itself, but when all data is valid i use the PHP:header() to redirect to the
data.php that performs the database insertion. The problem is that the data
is not available to data.php in the

_POST变量中的data.php无法获得数据。我怎样才能克服这个问题呢？处理整个事情的任何其他微妙方式？任何帮助
赞赏。

_POST variable. How can i overcome this
problem? Any other subtle way to handle the whole thing? Any help
appreciated.

我会稍微改变一下这个功能。


1 。有一个对

I would break the function a little differently.

1. Have a form (view) that is sensitive to

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