需要有关以下项目的信息 [英] need information on the following items
问题描述
我想了解以下项目的一些信息....发给我什么信息u
有pls .....
1）Segmentaion Voilation
2）共享对象文件
3）虚函数
4）如何在c ++程序中调用ac函数，反之亦然？
5）堆栈的默认大小是多少？堆？
6）UNIX中的信令
请做必要的事情。谢谢。
Hi,
I want some info on the following items....send me what ever info u
have pls.....
1) Segmentaion Voilation
2) Shared Objects files
3) Virtual Functions
4) How can I call a c function in a c++ program and vice versa?
5) what is the default size of a stack and heap ?
6) Signalling in UNIX
Pls do the needful. Thank you.
推荐答案
" Rajnee Kanth" < RA ********* @ gmail.com>在消息中写道
news：11 ********************** @ g44g2000cwa.googlegr oups.com ...
"Rajnee Kanth" <ra*********@gmail.com> wrote in message
news:11**********************@g44g2000cwa.googlegr oups.com...
我想了解以下项目的一些信息....发给我什么信息你有什么信息.....
1）Segmentaion Voilation
2）共享对象文件
3）虚拟功能
4）如何在c ++程序中调用ac功能反之亦然？
5）堆栈和堆的默认大小是什么？
6）UNIX中的信令
请做好帮助。谢谢。
Hi,
I want some info on the following items....send me what ever info u
have pls.....
1) Segmentaion Voilation
2) Shared Objects files
3) Virtual Functions
4) How can I call a c function in a c++ program and vice versa?
5) what is the default size of a stack and heap ?
6) Signalling in UNIX
Pls do the needful. Thank you.
3/4 - 去问comp.lang.c ++
5 - C一无所知这样的事情
6 - 在Unix组上询问
2 - 你的意思是什么？
1 - 你访问你不拥有的记忆
3/4 - go and ask on comp.lang.c++
5 - C knows nothing about such things
6 - ask on a Unix group
2 - what do you mean?
1 - you accesses memory you didn''t own
Rajnee Kanth写道：
Rajnee Kanth wrote:
我想了解以下项目的一些信息....给我发送任何信息，请给我.....
1）Segmentaion Voilation
从未听说过它。我已经写了四十年的程序（以及
bug），这是第一次提到
Segmentaion或Voilation我见过。这一定是
某种新技术你应该问你的教授
;我太落后了，无法帮助你。
2）共享对象文件
没有这样的事情。 C对象是内存驻留的;
a文件中的数据不符合对象的条件。
3）虚函数
你有拼写错误的贤惠 "一个良性的功能是一个没有副作用的
;这些也被称为纯粹的函数。
4）如何在c ++程序中调用c函数，反之亦然？
两种方向都不可能。
a C程序中的所有函数都是C，所以没有C ++函数可以调用。
同样，C ++程序只包含C ++函数（有些是
可能看起来很像C，但是如果它们存在于C ++程序中
C ++规则占上风。）
5）堆栈的默认大小是多少？堆？
堆栈：二十三个板块，两个在轮辋上有筹码。
堆：2.2立方码的快速硬化混凝土。
6）UNIX中的信令
UNIX在这里是偏离主题的。尝试alt.lang.cobol。
请做必要的事情。
我试图效仿你的榜样，尽可能多地花费你需要的b / b $
谢谢。
Hi,
I want some info on the following items....send me what ever info u
have pls.....
1) Segmentaion Voilation
Never heard of it. I''ve been writing programs (and
bugs) for forty years, and this is the first mention of
"Segmentaion" or of "Voilation" I''ve seen. This must be
some kind of new technology you should ask your professor
about; I''m too far behind the times to help you.
2) Shared Objects files
No such thing. C objects are memory-resident; data in
a file does not qualify as an object.
3) Virtual Functions
You''ve misspelled "virtuous." A virtuous function is one
that has no side-effects; these are also called "pure" functions.
4) How can I call a c function in a c++ program and vice versa?
Not possible, in either direction. All functions in
a C program are C, so there are no C++ functions to call.
Similarly, a C++ program contains only C++ functions (some
may look a lot like C, but if they reside in a C++ program
the C++ rules prevail).
5) what is the default size of a stack and heap ?
Stack: twenty-three plates, two with chips on the rims.
Heap: 2.2 cubic yards of rapidly hardening concrete.
6) Signalling in UNIX
UNIX is off-topic here. Try alt.lang.cobol.
Pls do the needful.
I''ve tried to follow your example, doing as much of the
needful as you seem to have done.
Thank you.
你非常欢迎 - 但只有一次。现在，请
消失。
-
Eric Sosman
es ***** @ acm-dot-org.inva lid
You''re more than welcome -- but only once. Now, please
go away.
--
Eric Sosman
es*****@acm-dot-org.invalid
Eric Sosman< es ***** @ acm-dot-org.invalid>写道：
Eric Sosman <es*****@acm-dot-org.invalid> wrote:
你有拼写错误的贤惠。良性功能是一种没有副作用的功能;这些也被称为纯粹的函数。
You''ve misspelled "virtuous." A virtuous function is one
that has no side-effects; these are also called "pure" functions.
我认为是良性的函数是一个表现为
程序员意图的方式。 :-)
-
Christopher Benson-Manica |我*应该*知道我在说什么 - 如果我
ataru（at）cyberspace.org |不，我需要知道。火焰欢迎。
I thought a "virtuous" function was one that behaved the way the
programmer intended. :-)
--
Christopher Benson-Manica | I *should* know what I''m talking about - if I
ataru(at)cyberspace.org | don''t, I need to know. Flames welcome.
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