如何在结构中初始化和数组？ [英] How to initialize and array in a structure?
问题描述
如何在以下代码行中设置[0] = 3的值？
#include< stdio.h>
struct letter {
char a [0];
};
struct add {
struct letter addit;
};
int main（void）{
struct add test;
返回0;
}
当我尝试类似test.add = 3或test.addit.a = 3时，
，编译器
给我警告
''赋值中的不兼容类型''。
提前致谢
Chad
Chad写道：
< blockquote class =post_quotes>如何在以下代码行中设置[0] = 3的值？
#include< stdio.h>
struct letter {
char a [0];
};
struct add {
struct letter addit;
};
int main（void）{
struct add test;
re转0;
}
当我尝试像test.add = 3或test.addit.a = 3时，编译器
给了我警告
' 分配中不兼容的类型。
提前致谢
Chad
char a [0]是零长度数组你不能把它设置成任何东西。
假设
char a [1];
试试
test .add [0] = 3;
Chad写道：如何在下面设置[0] = 3的值代码行？
#include< stdio.h>
结构字母{
char a [0];
C中不允许长度为0的数组.ITYM：
char a [1];
（这不是一个整体很有意义。）};
struct add {
struct letter addit;
};
int main（void）{
struct add test;
/ *赋值* /
test.addit.a [0] = 3;返回0;
}
当我尝试像test.add = 3或test.addit.a = 3时，编译器
给了我警告
' '赋值中的不兼容类型''。
当然，你需要意识到赋值和初始化是两个非常不同的东西。
要*初始化*'test''你写的值：
int main（void）{
struct add test = {{{3}}};
返回0;
}
HTH，
--g
-
Artie Gold - 德克萨斯州奥斯汀
http://goldsays.blogspot.com （新帖子8/5）
http://www.cafepress.com/goldsays
如果你没有什么可隐瞒的，你就是不要尝试！"
Artie Gold写道：Chad写道：如何在以下代码行中设置[0] = 3的值？
#include< stdio.h>
结构字母{
char a [0];
C中不允许长度为0的数组.ITYM：
char a [1 ];
（这也没有多大意义。）};
struct add {
struct letter addit;
};
int main（void）{
struct add test;
/ * assignment * /
test.addit.a [0] = 3;返回0;
}
当我尝试类似test.add = 3或test.addit.a = 3时，编译器
给了我警告
''赋值中不兼容的类型''。
当然，你需要意识到赋值和初始化是两个截然不同的东西。
要初始化*'test''你写的值：
int main（v oid）{
struct add test = {{{3}}};
返回0;
}
HTH，
--ag
-
Artie Gold - 德克萨斯州奥斯汀
http ：//goldsays.blogspot.com （新帖子8/5）
http://www.cafepress.com/goldsays
如果你没有什么可隐瞒的，你就不会尝试！
好的，我想我得到了这个。如果没有，我会在某个时候回到这里
明天会提出更多问题。
How do I set the value of a[0] = 3 in the following lines of code?
#include <stdio.h>
struct letter{
char a[0];
};
struct add {
struct letter addit;
};
int main(void) {
struct add test;
return 0;
}
when I try something like test.add=3 or test.addit.a=3, the compiler
gives me the warning
''incompatible types in assignment''.
Thanks in advance
Chad
Chad wrote:
How do I set the value of a[0] = 3 in the following lines of code?
#include <stdio.h>
struct letter{
char a[0];
};
struct add {
struct letter addit;
};
int main(void) {
struct add test;
return 0;
}
when I try something like test.add=3 or test.addit.a=3, the compiler
gives me the warning
''incompatible types in assignment''.
Thanks in advance
Chad
char a[0] is a zero length array you can not set it to any thing.
assuming
char a[1];
try
test.add[0]=3;
Chad wrote:How do I set the value of a[0] = 3 in the following lines of code?
#include <stdio.h>
struct letter{
char a[0]; An array with a length of 0 is not permitted in C. ITYM:
char a[1];
(Which doesn''t make a whole lot of sense either.) };
struct add {
struct letter addit;
};
int main(void) {
struct add test; /* assignment */
test.addit.a[0] = 3; return 0;
}
when I try something like test.add=3 or test.addit.a=3, the compiler
gives me the warning
''incompatible types in assignment''.
Of course, you need to realize that assignment and initialization are
two very different things.
To *initialize* the value of `test'' you''d write:
int main(void) {
struct add test = {{{3}}};
return 0;
}
HTH,
--ag
--
Artie Gold -- Austin, Texas
http://goldsays.blogspot.com (new post 8/5)
http://www.cafepress.com/goldsays
"If you have nothing to hide, you''re not trying!"
Artie Gold wrote:Chad wrote:How do I set the value of a[0] = 3 in the following lines of code?
#include <stdio.h>
struct letter{
char a[0];
An array with a length of 0 is not permitted in C. ITYM:
char a[1];
(Which doesn''t make a whole lot of sense either.)};
struct add {
struct letter addit;
};
int main(void) {
struct add test;
/* assignment */
test.addit.a[0] = 3;return 0;
}
when I try something like test.add=3 or test.addit.a=3, the compiler
gives me the warning
''incompatible types in assignment''.
Of course, you need to realize that assignment and initialization are
two very different things.
To *initialize* the value of `test'' you''d write:
int main(void) {
struct add test = {{{3}}};
return 0;
}
HTH,
--ag
--
Artie Gold -- Austin, Texas
http://goldsays.blogspot.com (new post 8/5)
http://www.cafepress.com/goldsays
"If you have nothing to hide, you''re not trying!"
Okay, I think I got this. If not, I''ll be back on here sometime
tommorrow asking more questions.
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