在结构初始化中初始化结构? [英] initialize a struct within a struct initialization?

问题描述

这听起来可能有些愚蠢，但我必须知道，因为我正在用 C 编写宾果游戏板.

This may sound somewhat stupid, but I have to know as I'm writing a bingo board in C.

#include <stdio.h>
typedef struct {
    int a;
    int b;
    int c;
    int d;
    int e;
} row;

typedef struct {
    row one;
    row two;
    row three;
    row four;
    row five;   
} bingo_board;

void initialize_columns()
{
    bingo_board board = {
    .one = {1, 2, 3, 4, 5},
    .two = {6, 7, 8, 9, 10},
    .three = {11, 12, 13, 14, 15},
    .four = {16, 17, 18, 19, 20},
    .five = {21, 22, 23, 24, 25}
    };
}

这可能吗?

推荐答案

很简单

void initialize_columns()
{
    bingo_board board = {
      {1, 2, 3, 4, 5},
      {6, 7, 8, 9, 10},
      {11, 12, 13, 14, 15},
      {16, 17, 18, 19, 20},
      {21, 22, 23, 24, 25}
    };
}

甚至像

void initialize_columns()
{
    bingo_board board = {
      1, 2, 3, 4, 5,
      6, 7, 8, 9, 10,
      11, 12, 13, 14, 15,
      16, 17, 18, 19, 20,
      21, 22, 23, 24, 25
    };
}

无需标记"每一行.不过，标记语法在 C99 中可用，并且您在示例中的内容已经适用于 C99.

No need to "tag" every row. The tagged syntax is available in C99 though, and what you have in your example is already correct for C99.

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