C ++初始化匿名结构 [英] C++ initialize anonymous struct

问题描述

我仍然收获我的C ++翅膀;我的问题是如果我有这样的结构：

I'm still earning my C++ wings; My question is if I have a struct like so:

struct Height
{
    int feet;
    int inches;
};

然后我有一些这样的行：

And I then have some lines like so:

Height h = {5, 7};
Person p("John Doe", 42, "Blonde", "Blue", h);

我喜欢通过花括号来初始化结构体，但我更喜欢上面的一行，在一个匿名的高度结构。我如何做到这一点？我最初的天真方法是：

I like the initialization of structs via curly braces, but I'd prefer the above be on one line, in an anonymous Height struct. How do I do this? My initial naive approach was:

Person p("John Doe", 42, "Blonde", "Blue", Height{5,7});

这没有工作。

推荐答案

你不能，至少不是在今天的C ++中;

You can't, at least not in present-day C++; the brace initialization is part of the initializer syntax and can't be used elsewhere.

您可以向 Height

You can add a constructor to Height:

struct Height
{
    Height(int f, int i) : feet(f), inches(i) { }
    int feet, inches;
};

这允许您使用：

Person p("John Doe", 42, "Blonde", "Blue", Height(5, 7));

不幸的是，由于 Height 聚合，你不能再使用大括号初始化。构造函数调用初始化也很容易，但：

Unfortunately, since Height is no longer an aggregate, you can no longer use the brace initialization. The constructor call initialization is just as easy, though:

Height h(5, 7);

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