更多关于化妆品（if-statements） [英] More on the cosmetics (if-statements)

问题描述

您更喜欢哪个：


/ * A * /


int k = 402;

if（k == 40）{

std :: cout<< 40 \ n;

}其他{

std :: cout<< 不是40 \ n;

}

/ * B * /

if（k == 40）std :: cout << 40 \ n;

其他std :: cout<< Not 40 \ n;

我知道这取决于品味，但我只是很好奇，并希望听到你的专业人士和'con''
s。

Which would you prefer:

/* A */

int k = 402;
if ( k == 40) {
std::cout << "40\n";
} else {
std::cout << "Not 40\n";
}
/* B */
if ( k == 40) std::cout << "40\n";
else std::cout << "Not 40\n";
I know it depends on taste but I am just curious and would like to hear
your pro''s and con''s.

推荐答案

桌面aécrit：

desktop a écrit :

您更喜欢哪种：


/ * A * /


int k = 402;

if（k == 40）{

std :: cout<< 40 \ n;

}其他{

std :: cout<< 不是40 \ n;

}


/ * B * /

if（k == 40） std :: cout<< 40 \ n;

其他std :: cout<< Not 40 \ n;


我知道这取决于品味，但我只是很好奇，想听听你的专业人士。和骗子。

Which would you prefer:

/* A */

int k = 402;
if ( k == 40) {
std::cout << "40\n";
} else {
std::cout << "Not 40\n";
}
/* B */
if ( k == 40) std::cout << "40\n";
else std::cout << "Not 40\n";
I know it depends on taste but I am just curious and would like to hear
your pro''s and con''s.

/ * C * /

// ...

const int magic_k = 402;

// ...

const int special_k = 40;

// k是......

int k = magic_k;

//

if（special_k == k）

{

std :: cout< ;< 40 \ n;

}

其他

{

std :: cout<< ; 不是40 \ n;

}


至于命题B，它在内部规范中被明确禁止

最后两个compagny我去过。


Michael

/* C */
// ...
const int magic_k = 402;
// ...
const int special_k = 40;
//k is ...
int k = magic_k;
//
if ( special_k == k )
{
std::cout << "40\n";
}
else
{
std::cout << "Not 40\n";
}

As for proposition B, it was explicitely forbidden in internal norm in
the last two compagny I''ve been.

Michael

5月31日下午3:13，桌面< ; ... ... @ sss.comwrote：

On May 31, 3:13 pm, desktop <[e-mail]:

您更喜欢哪种：


/ * A * /
std :: cout< 40 \ n;

}其他{

std :: cout<< 不是40 \ n;

}


/ * B * /

if（k == 40） std :: cout<< 40 \ n;

其他std :: cout<< Not 40 \ nn;


我知道这取决于品味，但我只是很好奇，想听听你的专业人士的b $ b和骗子。

Which would you prefer:

/* A */

int k = 402;
if ( k == 40) {
std::cout << "40\n";
} else {
std::cout << "Not 40\n";
}

/* B */
if ( k == 40) std::cout << "40\n";
else std::cout << "Not 40\n";

I know it depends on taste but I am just curious and would like to hear
your pro''s and con''s.

为了维护和后来的纠正/改进''A''更好;
更好;它可以防止因后期编辑而产生的算法错误并且

forggeting braces。

for the sake of maintanance and later correction/improvement ''A'' is
better ;it prevents algorithmic errors due to later editing and
forggeting braces.

desktop写道：

desktop wrote :

你更喜欢哪个：


/ * A * /


int k = 402;

if（k == 40）{

std :: cout<< 40 \ n;

}其他{

std :: cout<< 不是40 \ n;

}


/ * B * /

if（k == 40） std :: cout<< 40 \ n;

其他std :: cout<< Not 40 \ n;


我知道这取决于品味，但我很好奇，想听听你的

pro''和骗子。

Which would you prefer:

/* A */

int k = 402;
if ( k == 40) {
std::cout << "40\n";
} else {
std::cout << "Not 40\n";
}
/* B */
if ( k == 40) std::cout << "40\n";
else std::cout << "Not 40\n";
I know it depends on taste but I am just curious and would like to hear your
pro''s and con''s.

/ * C * /

if（k == 40）

std :: cout< < 40 \ n;

其他

std :: cout<< Not 40 \ n;;


我想在单独的行上使用括号，但是对于复合语句

只有一个内部产生太多混乱的声明，所以我不会为那些人使用大括号。


亲：它看起来更干净（至少对我来说）

Con：在扩展语句时你必须添加大括号，这可以忘记



- 西尔维斯特

/* C */
if (k == 40)
std::cout << "40\n";
else
std::cout << "Not 40\n";

I''d like to have braces on separate lines, but for compound statements
with only a single inner statement that produces too much clutter, so I
won''t use braces for those.

Pro: it looks cleaner (to me at least)
Con: you''ll have to add the braces when extending the statements, which
can be forgotten

- Sylvester

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