while循环使用mysqli_fetch_array和提交按钮 [英] While loop using mysqli_fetch_array with submit buttons
问题描述
问候，
目前我的代码是按照这种性质安排的，请原谅我这么新，我正在学习！ :)所以不要笑我的回声'因为我对表还不太了解。
我遇到的问题是我使用while循环显示5来自mysql数据库的数据行。但是，当我在循环中放置一个提交按钮时，它将正确循环5次，但是当点击任何提交按钮时，它将默认为检索到的最后一行数据的值。
这是我到目前为止的代码。
Greetings,
Currently my code is arranged in this nature, and please excuse me for being so new, I''m learning! :) So no laughing at my echo''s as I don''t know much about tables yet.
The issue I have is that I am using a while loop to display 5 rows of data from the mysql database. However when I put a submit button in the loop it will loop it 5 times properly but when any of the submit buttons are clicked it will default to the values from the last row of data retrieved.
Here''s what I have so far with code.
推荐答案
首先，它是
_POST [''PHP_SELF''] （带引号，否则会发出通知）。
判断你的表格，我会说它默认为没有排，因为它' s 5次完全相同的形式...
_POST[''PHP_SELF''] (with quotes, otherwise a notice is issued).
judging your form, I’d say it defaults to no row, since it’s 5 times exactly the same form …
感谢您看一下，我还在努力弄清楚如何让它运转起来。我不知道如何为循环中的每个输出制作不同的表格。
有什么建议吗？
编辑：忘了提到它默认为最后一行，并在我点击提交时做它应该做的事情。
Thanks for taking a look at it, I''m still trying to figure out how to get it working. I''m not sure how to make a different form for each of the outputs in the loop.
Any suggestions?
Forgot to mention it defaults to the last row and does what it should when I click submit.
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