mysqli_query，mysqli_fetch_array和while循环 [英] mysqli_query, mysqli_fetch_array and while loop

问题描述

我是PHP的新手，我正在尝试使用PHP建立一个网站.我有用于测试结果的本地主机，并且已经在网站上安装了phpmyadmin.

I am new to PHP and I am trying to build a website using PHP. I have localhost for testing the result and I have phpmyadmin already installed on the website.

我现在要做的是从数据库门户"中列出我的表属性"的内容，并用结果填充表.

What i am trying to do now, is to list the contents of my table "property" from database "portal" and fill a table with the results.

我正在使用mysqli_query，mysqli_fetch_array和while循环.我收到以下错误:

I am using mysqli_query, mysqli_fetch_array and while loop. I'm getting the following error:

警告:mysqli_fetch_array()期望参数1为mysqli_result， 在C:\ xampp \ htdocs \ falcon \ portal \ forms \ edit listing.php中给出的布尔值 在第15行

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in C:\xampp\htdocs\falcon\portal\forms\edit listing.php on line 15

session_start();
require_once "connect_to_mysql.php"; // where i store username and password to access    my db.

$sqlCommand = "SELECT * property FROM portal"; // dbname: portal - table: propery
$query = mysqli_query($myConnection, $sqlCommand);

$Displayproperty = '';
while ($row = mysqli_fetch_array($query))
$id = $row["pid"];
$title = $row["ptitle"];
$area = $row["parea"];
$city = $row["pcity"];
$Displayproperty .= '<table width="500" border="0" cellspacing="0" cellpadding="1">
<tr>
<td>' . $id . '</td>
<td>' . $title . '</td>
<td>' . $area . '</td>
<td>' . $city . '</td>
<td><a href="forms.php?pid=' . $id . '">Upload images</a><br /></td>
</tr>
</table>';

推荐答案

以此替换您的查询.确保您之前已添加此行.

Replace your query with this. Make sure you have added this line before.

$db = mysql_select_db('portal');

$sqlCommand = "SELECT * FROM property"; 

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