无符号整数？ [英] unsigned integer?
问题描述
这是一个天真的问题：
"％u" ％-3
我希望它打印3.但它仍然打印-3。
另外，如果我有一个int，我可以将它转换为C中的unsigned int：
int i = -3;
int ui =（unsigned int）i;
有没有办法在Python中执行此操作？
This is a naive question:
"%u" % -3
I expect it to print 3. But it still print -3.
Also, if I have an int, I can convert it to unsigned int in C:
int i = -3;
int ui = (unsigned int)i;
Is there a way to do this in Python?
推荐答案
3月10日上午11:32，杰克 < nos ... @ invalid.comwrote：
On Mar 10, 11:32 am, "Jack" <nos...@invalid.comwrote:
这是一个天真的问题：
"％u" ％-3
我希望它打印3.但它仍然打印-3。
另外，如果我有一个int，我可以将它转换为C中的unsigned int：
int i = -3;
int ui =（unsigned int）i;
有没有办法在Python中执行此操作？
This is a naive question:
"%u" % -3
I expect it to print 3. But it still print -3.
Also, if I have an int, I can convert it to unsigned int in C:
int i = -3;
int ui = (unsigned int)i;
Is there a way to do this in Python?
def unsigned（n）：
return n& 0xFFFFFFFF
def unsigned(n):
return n & 0xFFFFFFFF
" Jack" < no **** @ invalid.comwrote：
"Jack" <no****@invalid.comwrote:
这是一个天真的问题：
"％u" ; ％-3
我希望它打印3.但它仍然打印-3。
This is a naive question:
"%u" % -3
I expect it to print 3. But it still print -3.
在内部，它使用C运行时来格式化数字，但是如果数字
你要求它打印unsigned是负数它使用％ d而不是％u。我有点b $ b不知道是否实际上可能为％d提供不同的输出而不是
％u。
Internally it uses the C runtime to format the number, but if the number
you ask it to print unsigned is negative it uses %d instead of %u. I have
no idea if it is actually possibly to get a different output for %d versus
%u.
>
另外，如果我有一个int，我可以将它转换为C中的unsigned int：
int i = -3;
int ui =（unsigned int）i;
有没有办法在Python中执行此操作？
>
Also, if I have an int, I can convert it to unsigned int in C:
int i = -3;
int ui = (unsigned int)i;
Is there a way to do this in Python?
取决于你想要它如何转换：
i = -3
ui = abs（i）
print ui
ui =（i& 0xffff）＃对于16位整数
print ui
ui =（i& 0xffffffff）＃对于32位整数
打印ui
ui =（i& 0xffffffffffffffff）＃64位整数
print ui
ui =（i& 0xffffffffffffffffffffffffffffffff）＃128位整数
打印ui
给出以下输出：
3
65533
4294967293
18446744073709551613
340282366920938463463374607431768211453
有一种将Python整数转换为无符号值的独特方式
这就是％u格式字符串无法做任何事情的原因除了打印
值。就个人而言，我已经预料到Python要么打印
绝对值或者抛出异常，但我想把它作为％d的别名
有点制作感觉也是如此。
Depeneding on how exactly you want it converted:
i = -3
ui = abs(i)
print ui
ui = (i & 0xffff) # for 16 bit integers
print ui
ui = (i & 0xffffffff) # for 32 bit integers
print ui
ui = (i & 0xffffffffffffffff) # for 64 bit integers
print ui
ui = (i & 0xffffffffffffffffffffffffffffffff) # for 128 bit integers
print ui
which gives the following output:
3
65533
4294967293
18446744073709551613
340282366920938463463374607431768211453
There isn''t a unique way to convert a Python integer to an unsigned value
which is why the %u format string cannot do anything other than print the
value. Personally I''d have expected the Python one to either print the
absolute value or throw an exception, but I guess making it an alias for %d
kind of makes sense as well.
Dan Bishop写道：
Dan Bishop wrote:
3月10日上午11点32分，杰克" < nos ... @ invalid.comwrote：
On Mar 10, 11:32 am, "Jack" <nos...@invalid.comwrote:
>这是一个天真的问题：
"％u" ％-3
我希望它打印3.但它仍然打印-3。
另外，如果我有一个int，我可以将它转换为C中的unsigned int ：
int i = -3;
int ui =（unsigned int）i;
有没有办法在Python中执行此操作？
>This is a naive question:
"%u" % -3
I expect it to print 3. But it still print -3.
Also, if I have an int, I can convert it to unsigned int in C:
int i = -3;
int ui = (unsigned int)i;
Is there a way to do this in Python?
def unsigned（n）：
返回n& 0xFFFFFFFF
def unsigned(n):
return n & 0xFFFFFFFF
或abs（-1）？
or abs(-1) ?
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