用C无符号整数 [英] unsigned integers in C

问题描述

当我运行程序下面的输出像109876543210-1-2-3-4-5-6-78-9-10-11-12和S0上。为什么这样？什么是无符号整数的概念？

 的main（）
   {
      无符号整型我;
       对于（I = 10; I＆GT; = 0;我 - ）
                 的printf（％D，我）;
   }
 

解决方案

无符号整数总是非负的，大于或等于0。当你从0减去1你结束了一个MAX_INT无符号整型

因此​​，你的循环不会终止。

不过，你需要的，如果你想让它打印无符号的价值，而不是符号值在你​​的printf用％U而不是％d按钮。

While i am running the program below it outputs like 109876543210-1-2-3-4-5-6-78-9-10-11-12-and s0 on. Why so? What is the concept of unsigned integer?

 main ()
   {
      unsigned int i;
       for (i = 10; i >= 0; i--)
                 printf ("%d", i);
   }

解决方案

Unsigned integers are always non-negative, that is greater than or equal to 0. When you subtract 1 from 0 in an unsigned integer type you end up with MAX_INT.

Therefore, your for loop will never terminate.

However, you need to use "%u" not "%d" in your printf if you want it to print the unsigned value rather than the signed value.

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