SimpleDateFormat的添加一些分钟 [英] SimpleDateFormat add some minutes
问题描述
我试着从一个JSONObject的分析日期
Im trying parse a date from a JSONObject
"timcre_not":"2013-12-11 21:25:04.800842+01"
和我解析与
mDate = new SimpleDateFormat("y-M-d h:m:s.SSSSSSZZ",
Locale.ENGLISH).parse(json.getString("timcre_not"));
但mDate值：
but the mDate value is:
Wed Dec 11 21:38:24 CET 2013
这是怎么回事？
What is happening?
推荐答案
由treeno 的答案是正确的。
The answer by treeno is correct.
作为一种替代方法，您可以使用第三方的开源乔达时 。乔达时经常被用来取代与java.util.Date和放大器;在Java中（和Android）。发现Calendar类
As an alternative, you can use the third-party open-source Joda-Time. Joda-Time is often used to supplant the java.util.Date & Calendar classes found in Java (and Android).
您的字符串是松散 ISO 8601 格式。替换空间与拉丁大写字母TT字得到了严格的ISO 8601格式。
The string you have is loosely in ISO 8601 format. Replace that SPACE with a LATIN CAPITAL LETTER T "T" character to get a strict ISO 8601 format.
乔达时的 日期时间 类接受了ISO 8601字符串直接给它的构造。一个陷阱：与java.util.Date，一个DateTime只追踪到毫秒不微秒。但在乔达时，而不是抛出一个错误，日期时间只是截断（忽略）额外的（超出3）位小数。
Joda-Time's DateTime class accepts an ISO 8601 string directly to its constructor. One catch: As with java.util.Date, a DateTime tracks only to the millisecond not microsecond. But in Joda-Time, rather than throw an error, the DateTime merely truncates (ignores) the extra (beyond 3) decimal places.
下面是一个使用乔达时2.3和Java 8的一些例子code。
Here is some example code using Joda-Time 2.3 and Java 8.
String input = "2013-12-11 21:25:04.800842+01";
String string = input.replace( " ", "T" ); // Replace SPACE with "T" for strict ISO 8601 format.
DateTime dateTimeUtc = new DateTime( string, DateTimeZone.UTC );
DateTimeZone timeZone = DateTimeZone.forID( "Europe/Paris" );
DateTime dateTimeParis = new DateTime( string, timeZone );
转储到控制台...
Dump to console…
System.out.println( "dateTimeUtc: " + dateTimeUtc );
System.out.println( "dateTimeParis: " + dateTimeParis );
在运行...
dateTimeUtc: 2013-12-11T20:25:04.800Z
dateTimeParis: 2013-12-11T21:25:04.800+01:00
爪哇8
我试图用新的java.time。* Java中的类8解析你的字符串。
Java 8
I tried using the new java.time.* classes in Java 8 to parse your string.
ZonedDateTime zonedDateTime = ZonedDateTime.parse( string );
不幸的是，解析器不容忍的时区偏移量是缩短 +01 。我尝试了更长的 +01：00 和它的工作。这似乎是一个缺陷，在Java实现，不是你的字符串。缩短的偏移是允许在ISO 8601。虽然两者我和RFC 3339使用preFER（ISO 8601的近轮廓）长 +01：00 中， ISO标准母鹿允许它，所以应该在java.time。*类。我提出错误编号：9009717与Oracle
Unfortunately, the parser did not tolerate the time zone offset being the shortened +01. I tried the longer +01:00 and it worked. This seems to be a flaw in the Java implementation, not your string. The shortened offset is allowed in ISO 8601. While both I and RFC 3339 (a near-profile of ISO 8601) prefer using the longer +01:00, the ISO standard doe allow it and so should the java.time.* classes. I filed Bug Id: 9009717 with Oracle.
如果可能的话，建议您日期他们所使用的更严格的和共同的ISO 8601格式包括源：
If possible, suggest to the source of your date that they use the more strict and common ISO 8601 format including:
- 使用字母T来代替空间的
- 在较长的时区偏移量，+01：00，而不是+01
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