编程问题的新手 [英] New to programming question
问题描述
这是来自非程序员Python教程的练习
作者：Josh Cogliati。
练习是：
编写一个程序，用户猜出你的名字，但他们只有3
的机会这样做，直到程序退出。
这是我的剧本：
--------------------------
count = 0
name = raw_input（猜猜我的名字。）
而名字！=''本''和计数< 3：
count = count + 1
if name！=''Ben''和count< 3：
name = raw_input（''再猜一次。''）
elif name ==''Ben''和count< 3：
打印你是对的！
否则：
打印''不再尝试。''
----------------------------------
一切都有效除了线：打印你是对的！
有人能告诉我出了什么问题并给我一个更好的选择
我想出了什么。
谢谢
本
This is an exercise from the Non-programmers tutorial for Python
by Josh Cogliati.
The exercise is:
Write a program that has a user guess your name, but they only get 3
chances to do so until the program quits.
Here is my script:
--------------------------
count = 0
name = raw_input("Guess my name. ")
while name != ''Ben'' and count < 3:
count = count + 1
if name != ''Ben'' and count < 3:
name = raw_input(''Guess again. '')
elif name == ''Ben'' and count < 3:
print "You''re right!"
else:
print ''No more tries.''
----------------------------------
Everything works except the line: print "You''re right!"
Could someone tell me what is wrong and give me a better alternative to
what I came up with.
Thank you
Ben
推荐答案
Ben写道：
这是来自非程序员的Python教程的练习
作者：Josh Cogliati。
练习是：
编写一个让用户猜出你的名字的程序，但只有3个机会这样做才能退出程序。
<这是我的剧本：
--------------------------
count = 0
name = raw_input（猜猜我的名字。）
而名字！=''Ben''和count< 3：
count = count + 1
如果名字！=''本''和计数< 3：
name = raw_input（''再猜一次。''）
elif name ==''Ben''和count< 3：
打印你是对的！
其他：
打印''不再尝试。''
------ ----------------------------
一切都有效除了线：打印你是对的！
有人能告诉我出了什么问题
while循环中的代码（即缩进的所有内容）仅在
时执行
while条件为真，即name！= Ben和count< 3
所以姓名==''Ben''：永远是假的，你是对的！将永远不会打印
并给我一个更好的替代方案。
只是一个提示：如果你分开，你可能会找到一个更清洁的解决方案测试名称
来自计数测试。
谢谢
本
This is an exercise from the Non-programmers tutorial for Python
by Josh Cogliati.
The exercise is:
Write a program that has a user guess your name, but they only get 3
chances to do so until the program quits.
Here is my script:
--------------------------
count = 0
name = raw_input("Guess my name. ")
while name != ''Ben'' and count < 3:
count = count + 1
if name != ''Ben'' and count < 3:
name = raw_input(''Guess again. '')
elif name == ''Ben'' and count < 3:
print "You''re right!"
else:
print ''No more tries.''
----------------------------------
Everything works except the line: print "You''re right!"
Could someone tell me what is wrong
The code within the while loop (i.e., everything indented) is executed only if
the while condition is true, i.e., name != Ben and count < 3
So name == ''Ben'': will always be false and "You''re right!" will never get printed
and give me a better alternative to what I came up with.
Just a hint: you may find a cleaner solution if you separate the tests for name
from the test for count.
Thank you
Ben
HTH
Michael
HTH
Michael
2005年3月31日20:03:00 -0800，"本" <是********* @ gmail.com>写道：
On 31 Mar 2005 20:03:00 -0800, "Ben" <be*********@gmail.com> wrote:
有人可以告诉我出了什么问题，并给我一个更好的选择
我想出了什么。
Could someone tell me what is wrong and give me a better alternative to
what I came up with.
从测试中分离原始输入语句。你的elsif是跳过它的
。
在你的
语句之后立即尝试只使用一个原始输入语句。 />
Ron
Seperate you raw input statements from your test. Your elsif is
skipping over it.
Try using only one raw imput statement right after your while
statement.
Ron
Ben写道：
这是非程序员的练习Python教程由Josh Cogliati撰写。
练习是：
编写一个程序，用户猜出你的名字，但他们只得到3 机会退出之前有机会这样做。
这是我的剧本：
------------------- -------
count = 0
name = raw_input（猜猜我的名字。）
同时名字！=''本''和计数< 3：
此循环内的所有内容只会在名称不等于
''Ben'且计数小于3时出现。
count = count + 1
你将计数增加一，这样可以让你的代码抓住案件
where count = 2，现在等于3.
如果名字！=''本''和计数< 3：
name = raw_input（''再猜一次。''）
elif name ==''Ben''和count< 3：
打印你是对的！
否则：
打印''不再尝试。''
这是为什么你得到这个打印信息，因为数量现在等于3.
--------------------------- -------
一切都有效除了线：打印你是对的！
但是程序没有机会打印不再需要
尝试。因为这个循环里面没有任何意义==''Ben''。
有人可以告诉我出了什么问题，给我一个更好的选择
我想出了什么。
谢谢
本
This is an exercise from the Non-programmers tutorial for Python
by Josh Cogliati.
The exercise is:
Write a program that has a user guess your name, but they only get 3
chances to do so until the program quits.
Here is my script:
--------------------------
count = 0
name = raw_input("Guess my name. ")
while name != ''Ben'' and count < 3:
Everything inside this loop will only occur if the name doesn''t equal
''Ben'' and the count is less than 3.
count = count + 1
You increase the count by one, which allows your code to catch the case
where count = 2 and now equals 3.
if name != ''Ben'' and count < 3:
name = raw_input(''Guess again. '')
elif name == ''Ben'' and count < 3:
print "You''re right!"
else:
print ''No more tries.''
Which is why you get this print message, because count is now equal to 3.
----------------------------------
Everything works except the line: print "You''re right!"
But at no point does the program get an opportunity to print "No more
tries.'' because there is no point inside this loop where name == ''Ben''.
Could someone tell me what is wrong and give me a better alternative to
what I came up with.
Thank you
Ben
另外，你复制了大量的案例测试。您检查是否
名称在开始时是''Ben'，然后在循环内，并且计数相同
。
我试图写出一个解决这个问题的逻辑方法，但实际上这个特殊的用例并不是那么简单吗？
这里是我的贡献：
count = 0
＃获取第一个输入
name = raw_input（"猜我的名字："）
＃给傻逼两个额外的东西
而count< 2：
＃检查名称值
如果名称==''本''：
打印你是对的！"
break
else：
name = raw_input（"再试一次："）
＃当然，我们还没有检查过吸盘的最后一次猜测
＃所以我们现在必须这样做。
if count == 2：
如果名字==''本''：
打印你是对的！
其他：
打印不再为你试试!!!
希望这会有所帮助。
Joal
Also, you''re duplicating a lot of your case testing. You check to see if
the name is ''Ben'' at the start, and then inside the loop, and the same
for the counts.
I tried to write out a logical method of approaching this problem, but
in truth this particular use-case isn''t that simple is it?
Here''s my contribution anycase:
count = 0
# Get first input
name = raw_input("Guess my name: ")
# Give the sucker two extra goes
while count < 2:
# Check the value of name
if name == ''Ben'':
print "You''re right!"
break
else:
name = raw_input("Try again: ")
# Of course, we haven''t checked the sucker''s last guess
# so we have to do that now.
if count == 2:
if name == ''Ben'':
print "You''re right!"
else:
print "No more tries for you!!!"
Hope this helps.
Joal
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