找到所有指数头寸 [英] find all index positions

问题描述

嗨

说我有这样的字符串

astring =''abcd efgd 1234 fsdf gfds abcde 1234''

如果我想要的话找到哪个位置是1234，我怎样才能实现这一目标......？我想b / b
想要使用index（）但它只给我第一次出现。我想

知道两者的位置1234

谢谢

解决方案

>说我有这样的字符串

astring =''abcd efgd 1234 fsdf gfds abcde 1234''
如果我想找到哪个位置是1234，我怎么能实现这个...？我想使用index（），但它只给我第一次出现。我想知道
两者的位置1234

嗯，我不确定它的效率如何，但以下是

似乎是为我做的：

a =''abcd efgd 1234 fsdf gfds abcde 1234''
thing ='''1234''
offsets = [i for i in range（len（a））if
a.startswith（thing，i）] print offsets

[10,31]

HTH，


-tkc

mi *** **** @ hotmail.com 写道：

嗨
说我有这样的字符串
astring =''abcd efgd 1234 fsdf gfds abcde 1234''
如果我想找到哪个位置是1234，我怎么能实现这个......？我想使用index（）但它只给我第一次出现。我想知道两者的位置1234
谢谢

==========

def getAllIndex（aString = None，aSub = None）：

t = dict（）

c = 0

ndx = 0

而True：

试试：

ndx = aString.index（aSub，ndx）

t [c] = ndx

ndx + = 1

c + = 1

除了ValueError：

break

返回t

===========


这将返回找到的字典;即，

getAllIndex（''abcd 1234 efgh 1234 ijkl''，''1234''）

{0：5,1：15}

alisonken1写道：

==========
def getAllIndex（aString = None，aSub = None）：
t = dict（）
c = 0
ndx = 0
同时为真：
尝试：
ndx = aString.index（aSub，ndx）
t [c] = ndx
ndx + = 1
c + = 1
除了ValueError：
break
return t
===========

这将返回找到的字典;即，

getAllIndex（''abcd 1234 efgh 1234 ijkl''，''1234''）

{0：5,1：15}

从0开始的连续整数作为键？看起来你想要一个清单

而不是一个字典。


彼得

hi
say i have string like this
astring = ''abcd efgd 1234 fsdf gfds abcde 1234''
if i want to find which postion is 1234, how can i achieve this...? i
want to use index() but it only give me the first occurence. I want to
know the positions of both "1234"
thanks

解决方案

> say i have string like this

astring = ''abcd efgd 1234 fsdf gfds abcde 1234''
if i want to find which postion is 1234, how can i
achieve this...? i want to use index() but it only give
me the first occurence. I want to know the positions of
both "1234"

Well, I''m not sure how efficient it is, but the following
seemed to do it for me:

a = ''abcd efgd 1234 fsdf gfds abcde 1234''
thing = ''1234''
offsets = [i for i in range(len(a)) if a.startswith(thing, i)] print offsets

[10, 31]
HTH,

-tkc

mi*******@hotmail.com wrote:

hi
say i have string like this
astring = ''abcd efgd 1234 fsdf gfds abcde 1234''
if i want to find which postion is 1234, how can i achieve this...? i
want to use index() but it only give me the first occurence. I want to
know the positions of both "1234"
thanks

==========
def getAllIndex(aString=None, aSub=None):
t=dict()
c=0
ndx=0
while True:
try:
ndx=aString.index(aSub, ndx)
t[c]=ndx
ndx += 1
c += 1
except ValueError:
break
return t
===========

This will return a dictionary of what was found; i.e.,

getAllIndex(''abcd 1234 efgh 1234 ijkl'', ''1234'')

{0: 5, 1: 15}

alisonken1 wrote:

==========
def getAllIndex(aString=None, aSub=None):
t=dict()
c=0
ndx=0
while True:
try:
ndx=aString.index(aSub, ndx)
t[c]=ndx
ndx += 1
c += 1
except ValueError:
break
return t
===========

This will return a dictionary of what was found; i.e.,

getAllIndex(''abcd 1234 efgh 1234 ijkl'', ''1234'')

{0: 5, 1: 15}

Consecutive integers starting at 0 as keys? Looks like you want a list
instead of a dict.

Peter

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