128位十六进制数--->字串缓冲区 [英] 128-bit hex number ---> string buffer
问题描述
是否存在将128位十六进制数转换为字符串的函数？
Does a function exist to convert a 128-bit hex number to a string?
推荐答案
ern说：
ern said:
是否存在将128位十六进制数转换为字符串的函数？
Does a function exist to convert a 128-bit hex number to a string?
没有十六进制数这样的东西。十六进制是一个数字
表示系统，而不是一种数字。
如果你有一个十六进制表示，你已经*有一个字符串，并且
将字符串转换为字符串很简单。
-
Richard Heathfield
" ; Usenet是一个奇怪的地方 - dmr 29/7/1999
http://www.cpax.org.uk
电子邮件：rjh在上面的域名（但显然放弃了www）
There is no such thing as a "hex number". Hexadecimal is a numeric
representation system, not a kind of number.
If you have a hex representation, you already *have* a string, and
converting a string to a string is simple enough.
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at above domain (but drop the www, obviously)
" ern" < er ******* @ gmail.comwrites：
"ern" <er*******@gmail.comwrites:
是否存在将128位十六进制数转换为字符串的函数？
Does a function exist to convert a 128-bit hex number to a string?
开始时的数字是什么格式？我问，因为
指定一个数字是十六进制是奇怪的，如果它只是在一个整数变量中的
。通常，人们认为数字变量
只是有一个值，而且基数并不重要。另外：C
并不保证存在128位整数类型。
-
我错过了什么？"
--Dan Pop
What format is the number in to start out with? I ask because
it''s strange to specify that a number is in hex if it''s simply in
an integer variable. Normally, one thinks of a numeric variable
as simply having a value, and the base is not important. Also: C
doesn''t guarantee the existence of an 128-bit integer type.
--
"Am I missing something?"
--Dan Pop
Richard Heathfield写道：
Richard Heathfield wrote:
ern说：
ern said:
是否存在将128位十六进制数转换为字符串的函数？
Does a function exist to convert a 128-bit hex number to a string?
没有十六进制数这样的东西。十六进制是一个数字
表示系统，而不是一种数字。
如果你有一个十六进制表示，你已经*有一个字符串，并且
将字符串转换为字符串很简单。
-
Richard Heathfield
" ; Usenet是一个奇怪的地方 - dmr 29/7/1999
http://www.cpax.org.uk
电子邮件：rjh在上面的域名（但显然放弃了www）
There is no such thing as a "hex number". Hexadecimal is a numeric
representation system, not a kind of number.
If you have a hex representation, you already *have* a string, and
converting a string to a string is simple enough.
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at above domain (but drop the www, obviously)
让我改写一下。我有一个128位的值，我希望将它变成一个十六进制表示的字符串。
例如，
如果我的128位值（以十六进制表示）是：
4D9479E256DD4E8A923E32065141A911
charBuffer =" 4D9479E256DD4E8A923E32065141A911"
Let me rephrase. I have a 128 bit value, which I would like to be
converted to a hexadecimally represented string.
For example,
If my 128 bit value (represented hexadecimally) was:
4D9479E256DD4E8A923E32065141A911
I would want this function to populate a char buffer such that:
charBuffer = "4D9479E256DD4E8A923E32065141A911"
如果你有一个十六进制表示，你已经*有*一个字符串，并且
将字符串转换为字符串很简单。
If you have a hex representation, you already *have* a string, and
converting a string to a string is simple enough.
上次检查时... http://www.asciitable.com/
字符串表示4具有十六进制值0x34，与上述语句相矛盾。你*总是*有一个字符串（如在这个
的情况下）它可能不是你需要的那个。
Last time I checked... http://www.asciitable.com/
the string representation "4" has the hex value 0x34, contradicting
your above statement. You *always* have a string, though (as in this
case) it might not be the one you need.
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