打印十六进制的数组字符缓冲区 [英] Printing char buffer in hex array

问题描述

我读512个字符到缓冲区，并想以十六进制显示它们。我尝试以下方法，但它只是所有的时间输出值相同，尽管不同的值应该在网络上被接收到。

I am reading 512 chars into a buffer and would like to display them in hex. I tried the following approach, but it just outputs the same value all the time, despite different values should be received over the network.

char buffer[512];
bzero(buffer, 512);
n = read(connection_fd,buffer,511);
if (n < 0) printf("ERROR reading from socket");
printf("Here is the message(%d): %x\n\n", sizeof(buffer), buffer);

难道我在这里输出缓冲区数组的地址，而不是它的内容？有没有用C一个简单的方法完成这个任务还是我需要写我自己的子程序？

Is it possible that here I am outputting the address of the buffer array, rather than its content? Is there an easy way in C for this task or do I need to write my own subroutine?

推荐答案

这将读取相同的512字节的缓冲区，但相互转换的字符的十六进制输出：

This will read the same 512 byte buffer, but convert each character to hex on output:

char buffer[512];
bzero(buffer, 512);
n = read(connection_fd,buffer,511);
if (n < 0) printf("ERROR reading from socket");

printf("Here is the message:n\n");
for (int i = 0; i < n; i++)
{
    printf("%02X", buffer[i]);
}

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