"临时"变量 [英] "Temporary" Variable
问题描述
问题：我希望运行一个无限循环并在每次迭代时初始化
上的变量。有点像，输入数据，测试它，不好！，下一页
试试？，测试它等等。我试过的只是简单的1：var1 =
raw_input，test var1，然后再次循环。结果是什么
var1获取并保持它收到的第一个值。如果这是在常见问题解答中，我很抱歉，我没有找到它。提前谢谢。
Problem: I wish to run an infinite loop and initialize a variable on
each iteration. Sort of like, "Enter Data", test it, "No good!", "Next
Try?", test it, etc. What I''ve tried is simply while 1: var1 =
raw_input, test var1, then run through the loop again. What results is
var1 gets and keeps the first value it receives. If this is in the FAQ,
my apologies, I did not find it. Thank you in advance.
推荐答案
我尝试了这段代码并且工作正常：
而1：
var1 = raw_input（"输入数字："）
print"您输入："，var1
var1 = int（var1）+ 1
print var1
I tried this code and it worked fine:
while 1:
var1 = raw_input("Enter a number: ")
print "You entered:",var1
var1 = int(var1) + 1
print var1
da ******** @ gmail.com 写道：
da********@gmail.com wrote:
问题：我希望运行无限循环并在每次迭代时初始化一个变量。有点像，输入数据，测试它，不好！，下一步
试试？，测试它等等。我试过的只是1：var1 =
raw_input，测试var1，然后再次运行循环。结果是什么
var1获取并保持它收到的第一个值。
Problem: I wish to run an infinite loop and initialize a variable on
each iteration. Sort of like, "Enter Data", test it, "No good!", "Next
Try?", test it, etc. What I''ve tried is simply while 1: var1 =
raw_input, test var1, then run through the loop again. What results is
var1 gets and keeps the first value it receives.
嗯。我收到语法错误。
Hmmm. I get a syntax error.
1：
.... var1 = raw_input
.... test var1
文件"< stdin>"，第3行
测试var1
^
语法错误：语法无效
如何发布实际代码？
你可以试试这个：
而1：
var = raw_input（给我一些数据！ ;）
if var ==some data：
print" Success！"
break
else：
打印不好，再试一次。
-
史蒂文。
.... var1 = raw_input
.... test var1
File "<stdin>", line 3
test var1
^
SyntaxError: invalid syntax
How about posting your actual code?
You could try this:
while 1:
var = raw_input("Give me some data! ")
if var == "some data":
print "Success!"
break
else:
print "No good, try again."
--
Steven.
Steven D''Aprano写道：
Steven D''Aprano wrote:
da ******** @ gmail.com 写道：
da********@gmail.com wrote:
问题：我希望运行一个infin迭代循环并在每次迭代时初始化一个变量。有点像，输入数据，测试它，不好！，下一步
试试？，测试它等等。我试过的只是1：var1 =
raw_input，测试var1，然后再次运行循环。结果是什么
var1获得并保持它收到的第一个值。
嗯。我收到语法错误。
Problem: I wish to run an infinite loop and initialize a variable on
each iteration. Sort of like, "Enter Data", test it, "No good!", "Next
Try?", test it, etc. What I''ve tried is simply while 1: var1 =
raw_input, test var1, then run through the loop again. What results is
var1 gets and keeps the first value it receives.
Hmmm. I get a syntax error.
>>> 1：
>>> while 1:
... var1 = raw_input
... test var1
文件"< stdin>"，第3行
测试var1
^
SyntaxError：语法无效
发布实际代码怎么样？
... var1 = raw_input
... test var1
File "<stdin>", line 3
test var1
^
SyntaxError: invalid syntax
How about posting your actual code?
Soitenly。
＃！/ usr / bin / python
#simple猜谜游戏，带数字
随机导入
spam = random.randint（1 ，100）
打印垃圾邮件#debugging目的
而1：
guess = raw_input（"你的猜测是什么，朋友？ ）
如果猜= =垃圾邮件：
print"你知道了！干得好。
休息
elif guess<垃圾邮件：
打印抱歉，太低了。再试一次。
elif guess>垃圾邮件：
打印抱歉，太高了。再试一次。
else：
print" you guessed，猜猜你可以试试这个：
而1：
var = raw_input（"给我一些数据！）
如果var ==一些数据：
打印成功！
打破
否则：
打印不好，再试一次。
适用于字符串以及some_data时效果很好是硬编码的。当某些数据出现问题时，我会将
置于麻烦之中被替换为数字，不带引号。它只需要说不好，等等。 -
史蒂文。
Soitenly.
#!/usr/bin/python
#simple guessing game, with numbers
import random
spam = random.randint(1, 100)
print spam #debugging purposes
while 1:
guess = raw_input("What''s your guess, friend? ")
if guess == spam:
print "You got it! Nicely done."
break
elif guess < spam:
print "Sorry, too low. Try again."
elif guess > spam:
print "Sorry, too high. Try again."
else:
print "You guessed ", guess You could try this:
while 1:
var = raw_input("Give me some data! ")
if var == "some data":
print "Success!"
break
else:
print "No good, try again."
That works fine with strings and when "some_data" is hardcoded. I run
into trouble when "some data" is replaced with a number, unquoted. It
simply says "No good, etc" --
Steven.
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