替换＆QUOT;＃＆QUOT;，＆QUOT; $＆QUOT;，＆QUOT;％＆QUOT;，＆QUOT;＆放大器;＆QUOT;和＆QUOT; _＆QUOT;与＆QUOT; \\＃＆QUOT;，＆QUOT; \\ $＆QUOT;，＆QUOT; \\％QUOT;，＆QUOT; \\＆安培;＆QUOT;和＆QUOT; \\ _＆QUOT; [英] Replacing "#", "$", "%", "&", and "_" with "\#", "\$", "\%", "\&", and "\_"

问题描述

我有一个纯文本文件，我想里面编译LaTeX的。但是，有时它具有字符＃，$，％，＆放大器;，和_。在LaTeX的正确编译，我必须首先以＃，\\ $，\\％，将这些字符替换\\＆安培;和_。我在使用该行 SED ：

I have a plain text document, which I want to compile inside LaTeX. However, sometimes it has the characters, "#", "$", "%", "&", and "_". To compile properly in LaTeX, I must first replace these characters with "#", "\$", "\%", "\&", and "_". I have used this line in sed:

sed -i 's/\#/\\\#/g' ./file.txt
sed -i 's/\$/\\\$/g' ./file.txt
sed -i 's/\%/\\\%/g' ./file.txt
sed -i 's/\&/\\\&/g' ./file.txt
sed -i 's/\_/\\\_/g' ./file.txt

这是正确的？

不幸的是，这个文件太大无法打开任何图形用户界面软件，因此检查，如果我的 SED 行是用文本编辑器正确是困难的。我试着用的grep 搜索，但如预期的搜索无法正常工作（例如下面，我搜索包含$的行）：

Unfortunately, the file is too large to open in any GUI software, so checking if my sed line is correct with a text editor is difficult. I tried searching with grep, but the search does not work as expected (e.g. below, I searched for any lines containing "$"):

grep "\$" file.txt

• 什么是把\\在这些字符前面的最佳方式？


• 如何使用的grep 来成功地检查线路的替代品？


• What is the best way to put "\" in front of these characters?
• How can I use grep to successfully check the lines with the replacements?

推荐答案

您可以做一个单一的电话更换为 SED ：

You can do the replacement with a single call to sed:

sed -i -E 's/([#$%&_\])/\\&/g' file.txt

的＆安培; 在替换文本填写的任何单个字符用括号括起来。请注意，由于 \\ 是LaTeX的转义字符，你必须逃脱它，以及在原始文件。

The & in the replacement text fills in for whichever single character is enclosed in parentheses. Note that since \ is the LaTeX escape character, you'll have to escape it as well in the original file.

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