int到* char [英] int to *char
问题描述
您好，
如何将int转换为* char（请最好的方式）我知道几轮
关于方法我自己:)
谢谢
Hello,
How can I convert an int to a *char (best way please) I know a few round
about methods myself :)
Thank you
推荐答案
" Nitin Manoharan" <纳米****** @ bacon.math.uwaterloo.ca>在留言中写道
新闻：Pi ************************************ @培根。 math.uwaterloo.ca ...
"Nitin Manoharan" <nm******@bacon.math.uwaterloo.ca> wrote in message
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你好，
如何将int转换为* char（请最好的方式）我知道几轮
关于方法我自己：）
Hello,
How can I convert an int to a *char (best way please) I know a few round
about methods myself :)
您是否尝试过reinterpret_cast< char *>（an_int）或（char *）an_int？
DW
Have you tried reinterpret_cast<char*>(an_int) or (char*)an_int?
DW
" David White" < no.email@provided>在消息中写道
news：wx ****************** @ nasal.pacific.net.au ...
"David White" <no.email@provided> wrote in message
news:wx******************@nasal.pacific.net.au...
Nitin Manoharan <纳米****** @ bacon.math.uwaterloo.ca>在消息中写道
新闻：Pi ************************************ @ bacon。 math.uwaterloo.ca ...
"Nitin Manoharan" <nm******@bacon.math.uwaterloo.ca> wrote in message
news:Pi************************************@bacon. math.uwaterloo.ca...
你好，
如何将int转换为* char（请最好的方式）我知道几轮
关于方法我自己：）
Hello,
How can I convert an int to a *char (best way please) I know a few round
about methods myself :)
您是否尝试过reinterpret_cast< char *>（an_int）或（char *）an_int？
DW
Have you tried reinterpret_cast<char*>(an_int) or (char*)an_int?
DW
1.哎哟。 reinterpret_cast真的会伤害你。这就像是经历了一个
void *（事实上，我敢打赌，这就是它的实施方式）。我相信
reinterpret_cast< char *>（an_int）将为您提供由
表示的整数地址。例如：
int a = 4;
char * chr = reinterpret_cast< char *>（a）;
/ * IIRC，这应该是地址0x00000004（完全无效）。* /
2.（char *）an_int，IIRC，不合法。你必须经过有效的转换：
&（（char *）an_int），我认为这可以隐含于做& an_int
（自动转换为char * ）
1. Ouch. reinterpret_cast can really hurt you. It''s like going through a
void* (in fact, I''ll bet that''s how it''s implemented). I believe that
reinterpret_cast<char*>(an_int) will give you the address represented by
that integer. For example:
int a = 4;
char* chr = reinterpret_cast<char*>(a);
/*IIRC, this should be the address 0x00000004 (not at all valid).*/
2. (char*)an_int, IIRC, is not legal. You must go through valid conversions:
&((char*)an_int), which I believe can be implicit by doing &an_int
(automatically converted to char*)
" MiniDisc_2k2" <马****** @ nospam.com>在消息中写道
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news:DB*****************@news2.east.cox.net...
大卫怀特 < no.email@provided>在消息中写道
新闻：wx ****************** @ nasal.pacific.net.au ...
"David White" <no.email@provided> wrote in message
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" Nitin马诺哈兰" <纳米****** @ bacon.math.uwaterloo.ca>在消息中写道
新闻：Pi ************************************ @ bacon。 math.uwaterloo.ca ...
"Nitin Manoharan" <nm******@bacon.math.uwaterloo.ca> wrote in message
news:Pi************************************@bacon. math.uwaterloo.ca...
你好，
如何将int转换为* char（请最好的方式）我知道几个
我自己围绕方法:)
您是否尝试过reinterpret_cast< char *>（an_int）或（char *）an_int？
DW
Hello,
How can I convert an int to a *char (best way please) I know a few round about methods myself :)
Have you tried reinterpret_cast<char*>(an_int) or (char*)an_int?
DW
1.哎哟。 reinterpret_cast真的会伤害你。这就像是经历了一个无效的*（事实上，我敢打赌，这就是它的实施方式）。我相信
reinterpret_cast< char *>（an_int）会给你
这个整数表示的地址。例如：
int a = 4;
char * chr = reinterpret_cast< char *>（a）;
/ * IIRC，这应该是地址0x00000004（不是完全有效）。* /
1. Ouch. reinterpret_cast can really hurt you. It''s like going through a
void* (in fact, I''ll bet that''s how it''s implemented). I believe that
reinterpret_cast<char*>(an_int) will give you the address represented by
that integer. For example:
int a = 4;
char* chr = reinterpret_cast<char*>(a);
/*IIRC, this should be the address 0x00000004 (not at all valid).*/
是的，我知道它很讨厌，但如果这是OP想要做的......
2.（char *）an_int，IIRC，不合法。你必须通过有效的
转换：&（（char *）an_int），我相信这可以隐含于做& an_int
（自动转换为char *）
Yes, I know it''s nasty, but if that''s what the OP wants to do...
2. (char*)an_int, IIRC, is not legal. You must go through valid
conversions: &((char*)an_int), which I believe can be implicit by doing &an_int
(automatically converted to char*)
根据The D& C ++的E，reinterpret_cast用作替换旧式演员的符号
。我认为旧式演员可以做任何reinterpret_cast可以做的事情，也可能更多。
我的编译器很乐意接受（char *）an_int。
DW
According to The D & E of C++, reinterpret_cast was intended as a notation
to replace the old-style cast. I thought that old-style casts could do
anything that reinterpret_cast can do, and possibly more.
My compiler happily accepts (char*)an_int.
DW
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