C ++使用char输入到int终止循环 [英] C++ Terminate loop using a char input to int

问题描述

我试图输入值到一个大小为10的数组，但问题是，我想要如果用户想要输入4x4矩阵，他不需要完成，直到数组中的第10个元素，他可以简单地按f或任何字符，我试图使if（input =='f'），但它循环，直到数组的结尾。

I'm trying to input values into an array of size 10, but the problem here is that I want if the users wants to enter 4x4 matrix, he doesn't need to complete till the 10th element in the array, he can simply press 'f' or any character, I tried to make if(input == 'f') but it loops till the end of the array. How can this be solved?

int main() {
int input,flag=0, size=0;
int matrix[10][10] = {0};

for(int i=0; i<10; i++) {
    for(int j=0; j<10;j++) {
        cout << "Please enter data for Row " << i << " Column " <<j << " (-200 to terminate): \n";
        cin >> input;

        if(input == -200) {
            flag = 1;
            break;
        }
        else
            matrix[i][j] = input;
    }
    if(flag == 1)
        break;
    size++;
}

cout << "The determinant of the matrix is: " << determinant(matrix,size) << "\n";
return 0; }

推荐答案

您必须更改您阅读输入的策略的值。将令牌作为字符串读取。如果字符串的第一个字符是'f'，则中断循环。

You have to change your strategy of reading the input. Read the token as a string. If the first character of the string is 'f', the break out of the loop. Otherwise, extract the number from the string.

int main()
{
   std::string input;
   int flag=0;
   int size=0;
   int matrix[10][10] = {0};

   for(int i=0; i<10; i++) {
       for(int j=0; j<10;j++) {
           std::cout << "Please enter data for Row " << i << " Column " <<j << " (f to terminate): \n";
           std::cin >> input;

           if ( input[0] == 'f' ){
               flag = 1;
               break;
           }
           else
              matrix[i][j] = atoi(input.c_str());
       }
       if(flag == 1)
          break;
       size++;
   }
}

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