C-unsigned int到unsigned char数组的转换 [英] C - unsigned int to unsigned char array conversion

问题描述

我有一个无符号的整数(2个字节)，我想将其转换为无符号的char类型.通过搜索，我发现大多数人建议执行以下操作:

I have an unsigned int number (2 byte) and I want to convert it to unsigned char type. From my search, I find that most people recommend to do the following:

 unsigned int x;
 ...
 unsigned char ch = (unsigned char)x;

正确的方法吗?我问是因为无符号char是1个字节，我们将2个字节的数据强制转换为1个字节.

Is the right approach? I ask because unsigned char is 1 byte and we casted from 2 byte data to 1 byte.

为防止任何数据丢失，我想创建一个无符号char []数组并将单个字节保存到该数组中.我被困在以下几点:

To prevent any data loss, I want to create an array of unsigned char[] and save the individual bytes into the array. I am stuck at the following:

 unsigned char ch[2];
 unsigned int num = 272;

 for(i=0; i<2; i++){
      // how should the individual bytes from num be saved in ch[0] and ch[1] ??
 }

此外，我们如何将未签名的char [2]转换回unsigned int .

非常感谢.

推荐答案

在这种情况下，您可以使用memcpy:

You can use memcpy in that case:

memcpy(ch, (char*)&num, 2); /* although sizeof(int) would be better */

此外，如何将未签名的char [2]转换回unsigned int.

Also, how would be convert the unsigned char[2] back to unsigned int.

以同样的方式，只需反转memcpy的参数即可.

The same way, just reverse the arguments of memcpy.

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